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Virty [35]
3 years ago
5

Simplify and factor completely.

Mathematics
1 answer:
raketka [301]3 years ago
7 0
6x+4-2x=4x+4=4(x+1)

Answer is A.
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Is the following conditional true or false? If it is false, find a counterexample.
Inessa [10]
This statement is always true
3 0
3 years ago
Help please asap ASAP ASAP ASAP PLEADEEEEEEEEE​
xenn [34]
SOLUTION OF TRIANGLE:

a i) use this formula, a² = b² + c² - 2bc cos A

a² = 8² + 10² - 2(8)(10) cos 60
= 84
a = 9.17 cm

UW = 9.17 cm

ii) use formula no 12 as attached :

sin
to solve this,

( sin 40 / 11 ) x 9.17 = 0.5358511

press shift sin on ur calc & the answer is :


FUNCTION

a) f(x) = x-3
g(x) = x²-1

i) f(6) = 6-3

substitute x with the value given in the bracket into equation

f(6) = 6-3
= 3

ii) to do inverse function use this formula :

u = f(x)
u = x - 3

and then make x as the subject

x = u + 3

after that, just change u to x

f-1(x) = x + 3

iii) f [ g(2) ] = f [ g(-2) ] = 0

g(2) = (2)² - 1 g(-2) = (-2)² - 1

= 4 - 1 = 4 - 1
= 3 = 3

f(3) = 3-3
= 0





4 0
3 years ago
Susie spent 4 1/4 hours on Monday an 3 5/8 hours on Tuesday working on project. About how long did she spend working on project
adelina 88 [10]
4(1/4)+3(5/8)=
(4+3)+(1/4+5/8)
7+(2/8+5/8)
7+7/8
7 and 7/8

Hope I didn't mess up for your sake
5 0
4 years ago
Read 2 more answers
An amusement park line is moving about 4 feet every 15 minutes. At this rate, approximately how long will it take for a person a
algol13
4 * 4' = 16ft/hr

50' / 16' = 67.5 minutes
5 0
3 years ago
Assume that a procedure yeilds a binomial with n trial and the probability of success for one trial is p. Use the given values o
Alexeev081 [22]

The value of minimum usual value is, \mu-2\sigma=-119.2

The value of maximum usual value is, \mu+2\sigma=1311.2

Given the values of the parameters of Binomial Distribution are,

Total number of trials (n) = 1490

probability of success in one trial is (p) = 2/5

The probability of failure in on trial is given by,

q=1-p=1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}

For Binomial distribution we know that,

Mean (\mu)=np=1490\times\frac{2}{5}=596

and Standard Deviation (\sigma)=\sqrt{npq}=\sqrt{1490\times\frac{2}{5}\times\frac{3}{5}}=357.6

Now, calculating the required measurement we get,

The minimum usual value is given by,

Mean -2 Standard Deviation =\mu-2\sigma=596-2\times357.6=-119.2

The maximum usual value is given by,

Mean + 2 Standard Deviation =\mu+2\sigma=596+2\times357.6=1311.2

Hence the minimum and maximum usual values are -119.2 and 1311.2 respectively.

Learn more about Binomial Distribution here -

brainly.com/question/15246027

#SPJ10

4 0
3 years ago
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