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AlekseyPX
3 years ago
6

A) expand the product $(x-1)(x-2)(x-3)$.

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0
A. (x-1)(x²-5x+6)=x³-5x²+6x-x²+5x-6=x³-6x²+11x-6.
b. Check if 1 is a zero: 1+2-11-12=-20. x-1 is not a factor. Try x=-1: -1+2+11-12=0, so x+1 is a factor.
Divide the cubic by the zero -1 using synthetic division:

-1 | 1 2 -11 -12
1 -1 -1 12
—————
1 1 -12 | 0 = x²+x-12 = (x-3)(x+4).

So the cubic is (x+1)(x-3)(x+4).
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Hi! im not sure if my answer is correct or not can someone check me :)
Maslowich
It is correct goodluck
7 0
3 years ago
F(x)=(x+1)^(5)-5x-2 <br> Find F'(x) and zeros of F'(x)
KiRa [710]
Assuming you mean
f(x)=(x+1)^5-5x-2

first use chain rule on first part
derivitive of (x+1)⁵=5(x+1)⁴ times the derivitive of (x+1) which is 1
the first part is 5(x+1)⁴

derivitive of -5x is -5
derivitive of -2 is 0

we gots
f'(x)=5(x+1)⁴-5
find zeroes
0=5(x+1)⁴-5
5=5(x+1)⁴
1=(x+1)⁴
+/-1=x+1
-1+/-1=x
-2=x or 0=x

f'(x)=5(x+1)⁴-5
zeroes at x=-2 and x=0
3 0
3 years ago
sara compares to phone plans. plan A charges $99 for the phone plus $25 per month. plan B charges $39 for a phone and a $35 per
tino4ka555 [31]

Answer: 6th month

Step-by-step explanation:

Let the month where the plans cost the same be represented by x.

Plan A charges $99 for the phone plus $25 per month. This can be written as:

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Plan B charges $39 for a phone and a $35 per month. This can be written as:

= 39 + 35x

We then equate both equations and this will be:

99 + 25x = 39 + 35x

Collect like terms

99 - 39 = 35x - 25x

60 = 10x

x = 60/10

x = 6

The plan will cost the same in the 6th month.

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