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Misha Larkins [42]
3 years ago
7

Solve the word problem. Round your final result to the nearest hundredth.

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

1)Area of circle: 64\pi

2)Area of semicircles: 128\pi

3)Area of quarter-circles: 128\pi

4)Total area of pattern: 320\pi

Step-by-step explanation:

r = 8cm

Given: 1 circle, 4 semicircles, and 8 quarter-circles.

Area of a circle: \pi r^{2}

1) A = \pi r^{2} where r = 8

A = 64\pi

2) 4 semicircles = 2 circles

so the answer is 2*A = 128\pi

3) 8 quarter-circles = 2 circles

Therefore, the answer here is the same as the answer for #2!

4)There are 5 circles total because:

1 circle = 1 circle

4 semicircles divided by 2 = 2 circles (because \frac{1}{2} times 4)

8 quarter-circles divided by 4 (think about what "quarter" means) = 2 circles

So ... 1 + 2 + 2 = 5 circles

Now we need to find the area of 5 circles which is just 5*A

5*A = 320\pi

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Answer:

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Step-by-step explanation:

Given

\sqrt[3]{217}

Required

Solve

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f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

Take:

x = 216; \triangle x= 1

So:

f(x) = \sqrt[3]{x}

Substitute 216 for x

f(x) = \sqrt[3]{216}

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So, we have:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

f(215 + 1) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot f'(x)

To calculate f'(x);

We have:

f(x) = \sqrt[3]{x}

Rewrite as:

f(x) = x^\frac{1}{3}

Differentiate

f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}

Split

f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}

f'(x) = \frac{x^\frac{1}{3}}{3x}

Substitute 216 for x

f'(216) = \frac{216^\frac{1}{3}}{3*216}

f'(216) = \frac{6}{648}

f'(216) = \frac{3}{324}

So:

f(216) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot \frac{3}{324}

f(216) \approx 6  + \frac{3}{324}

f(216) \approx 6  + 0.0093

f(216) \approx 6.0093

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