Find a parameterization for the curve y=8−4x3 that passes through the point (0,8,4) when t=−1 and is parallel to the xy-plane.
1 answer:
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Answer:
A = 1 , 1 ,
Step-by-step explanation:
Given equation as
(2a -5) (a² -2a +1) = 0
Or, (2a - 5) (a - 1 )² = 0
Or, (2a - 5) (a - 1) (a - 1) = 0
So, value of a are :
2a - 5 =0, a - 1 =0, a- 1 = 0
i.e a =
and a = 1 , 1
Answer
Step-by-step explanation:
hence the value of y=-9/4and k=-16.
Answer:
POSTULATE
Step-by-step explanation:
<em>A postulate is a statement that is assumed true without proof. A theorem is a true statement that can be proven </em>
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<em>In geometry, the theorem is considered valid or correct with which its assertion is practically not refuted by almost anyone, whether it is really true or not. </em>
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<em>This, in practice, implies that all students of the subject share the same criteria on the theory. Thus, the postulates, in short, have the following characteristics: </em>
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<em> They are presumed true by most of the scholars in the field. </em>
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<em>Its contradiction goes against the very essence of the subject. </em>
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<em>Postulate 6: If two planes intersect, then their intersection is a line.</em>
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<em>See Attachment for Details ^^</em>
<em>The image attached represents the statement given in the question (If two distinct planes intersect, then their intersection is a line)</em>
<em>Therefore</em><em>, </em>
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<em>The Geometry term that represents the statement above is POSTULATE</em>
