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Leviafan [203]
3 years ago
6

Find a parameterization for the curve y=8−4x3 that passes through the point (0,8,4) when t=−1 and is parallel to the xy-plane.

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0
We Need more info please us at brainly would like you to provide more information so we can answer your question right away thank you have a goodnight
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We need a minimum of 30 book sales by today. If 10 books were sold yesterday, what are the possible numbers for sales today
amm1812

I mean it would be A and D because I don't know why they are both the same answer. If 10 books were sold yesterday, at LEAST 20 are needed to make the goal.

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3 years ago
I need help asap! 25 points
alukav5142 [94]

Answer:bc thats not the number included in the problem

Step-by-step explanation:

8 0
3 years ago
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2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes
jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3,  5,  4,  4,  3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

            X = 3,  5,  4,  4,  3

7 0
3 years ago
11-2 (1+3x) &lt; 39<br><br> Maths HW Please help
Paha777 [63]

Answer:

x>-5

Step-by-step explanation:

5 0
3 years ago
(60 points)
natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56

5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}

6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}

8 0
3 years ago
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