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3 years ago

Help me, please! ||x−5|+2|≤3

Mathematics

2 answers:

LekaFEV [45]3 years ago

6 0

Answer:

the answer to your question of finding x is,

x = 6

uranmaximum [27]3 years ago

4 0

The answer should be 6

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Use the theoretical method to determine the probability of the following event. A randomly selected person has a birthday in Nov

MakcuM [25]

Answer:

There is an 8.22% probability that a randomly selected person has a birthday in November.

Step-by-step explanation:

The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.

A randomly selected person has a birthday in November

There are 365 days in a year, so the number of total outcomes is 365.

There are 30 days in november, so the number of desired outcomes is 30.

So the probability is

$P = \frac{30}{365} = 0.0822$

There is an 8.22% probability that a randomly selected person has a birthday in November.

3 0

3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago

What is the value of [(3/5)^0]^-2

Finger [1]

I believe the answer is ‘1’ :)

4 0

3 years ago

An older TV screen was 11 centimeters wide. The

Montano1993 [528]

Answer:

The new TV screen is 12.1 centimeters wide.

Step-by-step explanation:

Find 10% of 11:

0.10 x 11 = 1.1

Add 1.1 to the original size.

11 + 1.1 = 12.1

hope this helps

4 0

3 years ago

Read 2 more answers

Based only on the given information, it is guaranteed that AD = CD.

pickupchik [31]

Answer:

Not really, actually it depends on the shape given whether it's a rectangle, a square etc. Because you can't conclude that the shape of a rectangle with such dimensions could be guaranteed.

5 0

3 years ago