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Alecsey [184]
4 years ago
10

Similarity Transformation

Mathematics
2 answers:
klio [65]4 years ago
7 0

Answer:

18 units

78

Step-by-step explanation:

Naily [24]4 years ago
4 0
The answer is
18 units
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(03.03 MC) Choose the graph below that correctly represents the equation 2x + 4y = 24. (5 points) Select one: a. line through th
Mnenie [13.5K]

Answer:

your line goes through both (0,6) and (12,0)

Step-by-step explanation:

Ok so you are describing some lines you see I think:

I see some of these as points you mentioned:

(0,6)  ,  (0,-6)  , (6,0)

So let's see which of these work:

(0,6)?

2(0)+4(6)=24

        24=24

(0,6) does work!

The other point you have listed with (0,6) is (12,0).

Let's try (12,0)

2(12)+4(0)=24

24+0=24

24=24

(12,0) works!

So your line goes through both (0,6) and (12,0)

7 0
3 years ago
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Name the polygon right whether it is a regular or not regular
Troyanec [42]
The polygon is regular
3 0
4 years ago
Read 2 more answers
find the slope of the line that contains the following points A : [ 17 , -12 ] and [ 17 , 8 ] and B [ 6 , -2 ] and [ -3 , 1 ]
Svetradugi [14.3K]
1/9 because i you plug in two of the points into y2 -y1 over x2 -x1 thats what you get.
4 0
4 years ago
Nikki and Jonathan both solve this system of equations:
xxTIMURxx [149]

Answer:

Jonathan's solution (0.4,2.12) is correct.

Step-by-step explanation:

Given system of equations are:

y = -2.7x+3.2\ \ \ \ \ \ \ y=1.3x +1.6

Now

The graph of the linear equation y= -2.7x+3.2 cuts the y-axis at the point (0,3.2) and x-axis at (1.185,0)

And the graph of the linear equation y= 1.3x+1.6 cuts the y-axis at the point (0,1.6) and x-axis at (-1.231,0)

And their point of intersection is (0.4,2.12)

And this is Jonathan's solution.

We can see from graph that point of intersection is (0.4,2.12)

4 0
3 years ago
Which quadrilateral's diagonals are congruent and perpendicular bisectors of each other?
AnnyKZ [126]

Diagonals congruent: rectangle, square, isosceles trapezoid

Perpendicular bisectors: Rhombus, Square

3 0
3 years ago
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