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4 years ago

Please help me out please

Mathematics

1 answer:

Natali [406]4 years ago

4 0

Answer:

w = 54°

Step-by-step explanation:

w is the inscribed angle subtended on the same arc with measure of 108°

w is half the size of the central angle, that is

w = 0.5 × 108° = 54°

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3 years ago

Abby sold half of her comic books and then bought seventeen more. She now has 32. With how many did she begin?

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3 years ago

Seamstress Jane has purchased 50 yards of red fabric and 110 yards of gold fabric to make red and gold curtains. What is the lar

Alisiya [41]

Answer: There are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

There are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

Step-by-step explanation:

Since we have given that

Number of yards of red fabric purchased by Jane = 50

Number of yards of gold fabric purchased by Jane = 110

We need to find the largest number of curtains she can make if she wants all the curtains to be exactly the same length.

For this we will find H.C.F. of 50 and 110.

Factors of 50 = 1, 2, 5, 10, 25, 50.

Factors of 110 = 1, 2, 5, 10, 11, 22, 55, 110.

So, Highest common factor of 50 and 110 is 10.

So, there are 10 largest number of curtains she can make if she wants all the curtains to be exactly the same length.

Number of yards of red fabric is given by

$\frac{50}{10}=5$

Number of yards of gold fabric is given by

$\frac{110}{10}=11$

Hence, there are 5 red fabrics and 11 gold fabrics that would be used for each curtain.

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3 years ago

Students pass a test it they score 50% or more. the marks of a large number of students were sampled and the mean and standard d

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So we are given that the mean is 42% and the sd (standard deviation) is 8%
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So one thing you should realize is that 42% + 8% is 50% which is passing. That is one standard deviation higher. So we use:

100 - 68 - 13.5 - 2.35 - 0.15 = 16. That means 16% of students passed the test. Which is terrible. They probably need to hit the books more.

Anyways if you have any question feel free to message me!
Hopes this helps!

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3 years ago