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victus00 [196]
3 years ago
13

Click to select the figure in the image that would portray the rotation of the given preimage and the rotation arrow,

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

plz explain correctly please

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Help me with 3, and 5 show your work !
ss7ja [257]
Okay so for number 3, you have to do the top work first.

3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!

5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
5 0
3 years ago
Suppose that, for a set of data, the range is x and the interquartile range is y. Which statement MUST be true? A) x = y B) x ≤
Vitek1552 [10]

c i suppose the answer

3 0
3 years ago
Read 2 more answers
How do you solve -2+6(-6x+6)?
Natali5045456 [20]

Answer: −36x+34

Step-by-step explanation:

Equation: −2+6(−6x+6)

Step 1. distribute the equation:

−2+(6)(−6x)+(6)(6)

−2+−36x+36

Step 2. Finally combine like terms:

−2+−36x+36

(−36x)+(−2+36)

−36x+34

Final Answer:

−36x+34

Hope I could help! :)

4 0
3 years ago
an initial investment of $9000 grows at an annual interest rate of 5% compounded continuously. how long will it take to double t
tino4ka555 [31]

Answer:

20 years

Step-by-step explanation:

9000/ 100= 900 = 10%

900/2= 450

450 x 2= 900

900 x 10= 9000

Now we multiply 10 by 2 because we doubled the value of our 450 into a 900 and now we get 20.

8 0
3 years ago
Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble
Paladinen [302]

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

The tree diagram

The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

5 0
3 years ago
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