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liq [111]
3 years ago
7

The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad

es at Lincoln Middle School. Two box and whisker plots are shown above a number line. The number line is scaled from 2 to 38 by twos. The first plot above the number line is labeled seventh grade. On the seventh grade plot: The left point is at 6. The left side of the box is at 14. The vertical segment inside the box is at 18 . The right side of the box is at 22. The right point of the plot is at 26. The eighth grade plot is above the seventh grade plot. On the eighth grade plot: The left point is at 22. The left side of the box is at 26. the vertical segment inside the box is at 30. The right side of the box is at 34. The right point of the plot is at 38. a) Describe the overlap of the two sets of data. b) Find the IQR of each set. c) Find the difference between the medians of the sets. d) What number multiplied by the IQR equals the difference between the medians of the two sets?
Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

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balu736 [363]

Answer:

8

Step-by-step explanation:

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7 0
2 years ago
The digit that makes 39,9?8 divisible by 9 is
Luden [163]

Answer:

?=7

Step-by-step explanation:

Here is a cool trick that I believe only works with 9.

Add the numbers, 3+9+9+8+x= divisible by 9.

3+9+9+7+8 is 36 which is the only number divisible by 9.

5 0
3 years ago
Can someone solve this for me please.
nika2105 [10]

Answer:

  • The value of PR is 21 ft.

Step-by-step explanation:

<u>We know that:</u>

  • 3(PQ + QT + TP) = PR + RS + SP
  • PQ = 7 ft.
  • QT = 4 ft
  • RS = 12 ft.

<u>Work:</u>

  • 3(PQ + QT + TP) = PR + RS + SP
  • => 3(7 + 4 + TP) = PR + 12 + SP
  • => 21 + 12 + 3TP = PR + 12 + SP
  • => 21 + 3TP = PR + SP
  • => 21 + SP = PR + SP                                                                       [3TP = SP]
  • => 21 = PR

Hence, <u>the value of PR is 21 ft.</u>

Hoped this helped.

BrainiacUser1357

6 0
2 years ago
The sum of 2 numbers (x and y) is 20, and their product is 51. What are the values of x and y
Murljashka [212]

Answer: 13&7

Step-by-step explanation:

The sum of two numbers x&y is 20

Product of the 2numbers xy is 51

X+y=20......equation 1

XY=51.........equation 2

X=20-y.......equation 3

Substitute for x inequation 3 into equation 2

So we have;

(20-y)y=51

Open the bracket

20y-y^2=51

Collect like terms,so we have

Y2-20y+51=0

Factorise

Factors of 51 is 13&7

So -13-7=-20 &-13×-7=51

Substitute

Y2-13y-7y+51=0

Y(y-13)-7(y-13)=0

(Y-7)(y-13)=0

Y-7=0

Y=7 or

Y-13=0

Y=13

Y=13 or 7

Substitute for y in equation 1

X+y=20

X+7=20

X=20-7

X=13 or

X+13=20

X=20-13

X=7

Therefore, X &Y = 13 &7

4 0
3 years ago
What is the volume of a figure that is 5cm,5cm,8cm,8cm,8cm,1cm
Ratling [72]

Answer:

the volume is 40 cm

Step-by-step explanation:

to find the volume all you need is length times width times height and you multiply it and that is your answer

7 0
3 years ago
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