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erastova [34]
4 years ago
14

Solve the problem. A student earned grades of C, A, B, and A in four different courses. Those courses had these corresponding nu

mbers of credit hours: 4, 5, 1, and 5. The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0. Compute the grade point average (GPA) and round the result to two decimal places. 3.40 3.50 8.75 2.18
Mathematics
1 answer:
Leno4ka [110]4 years ago
3 0

Answer:

3.40

Step-by-step explanation:

Given :  

A student earned grades of C, A, B, and A in four different courses.

Those courses had these corresponding numbers of credit hours: 4, 5, 1, and 5.

The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0.

To Find: Compute the grade point average (GPA) and round the result to two decimal places.

Solution :

The grades earned are C, A, B, and A

Since . The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0.

So the earned grades  C=2 , A=4 , B=3 , A =4

Their corresponding numbers of credit hours are 4,5,1,5

Formula of GPA   = \frac{Grades*credits}{\text{sum of credits}}

                             =\frac{4*2+4*5+3*1+4*5}{4+5+1+5}

                             =\frac{8+20+3+20}{15}

                             =\frac{51}{15}

                             = 3.40

Hence the grade point average (GPA) is 3.40

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