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1 answer:
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Answer:
{ c ∣ c ≠ 2 , 12, -1, 0, c ∈ R }
Step-by-step explanation:
Considering the set
As we know that
- A function is said to be a relation if every x-value has one and only one y-value.
So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0
Therefore,
{ c ∣ c ≠ 2 , 12, -1, 0, c ∈ R }