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3 years ago

Is it possible for a pair of nonadjacent angles to share a vertex ?

Mathematics

1 answer:

Hoochie [10]3 years ago

3 0

Yes with vertical Angles.
:) hope this helps

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A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri

pychu [463]

Y=300+40g
Y=5000
5000=300+40g
-300
4700=40g/40
117.5=g
About 117 people without going over budget.

5 0

3 years ago

A very, very hungry guy goes to a fast food place and orders 2 chicken sandwiches

siniylev [52]

Answer:

Step-by-step explanation:

Huhuj

6 0

3 years ago

Michelle found the area of a circle as 78.5 . She used 3.14 for π. What is the radius of the circle? Explain how you found your

NikAS [45]

Answer:

5 units

Step-by-step explanation:

Given:-

- The area of the circle was computed to be A = 78.5

- The value of π is estimated to be = 3.14

Find:-

What is the radius of the circle?

Solution:-

- The area of a circle (A) with radius ( r ) is computed by the following formula:

A = π*r^2

- Divide the equation by π :

r^2 = ( A / π )

- Take the square root of the entire equation:

r = √ ( A / π )

- Substitute the given values:

r = √ ( 78.5 / 3.14 )

- Resolve the fraction:

r = √25

- The perfect square root of 25

r = 5

Answer: The radius of the circle is r = 5 units

3 0

3 years ago

Read 2 more answers

The area model below shows a way to solve 7,776 ÷ 24 using place value. The 3 partial quotients missing from the model represent

Burka [1]

Answer: The answer is 324 all you have to do is just divide 7,776 by 24 then Breaking it into expanded form.

8 0

2 years ago

as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets

yKpoI14uk [10]

<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

parent-teacher conference = $35.50
school related assembly = $42
The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

<h3>Equations</h3><h3> $x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)$ </h3>

From equation (i)

$x+y = 27\\x = 27-y...equation(iii)\\$

Put equation(iii) into equation (ii)

$35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5$

Put y = 5 into equation 1

$x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22$

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

brainly.com/question/4074386

8 0

3 years ago

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