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77julia77 [94]
3 years ago
5

Is it possible for a pair of nonadjacent angles to share a vertex ?

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0
Yes with vertical Angles.
:) hope this helps
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A catering company charges $300 plus $40 per guest for a wedding. Sarah and Eric do not want to spend more than $5,000 on cateri
pychu [463]
Y=300+40g
Y=5000
5000=300+40g
-300
4700=40g/40
117.5=g
About 117 people without going over budget.
5 0
3 years ago
A very, very hungry guy goes to a fast food place and orders 2 chicken sandwiches
siniylev [52]

Answer:

Step-by-step explanation:

Huhuj

6 0
3 years ago
Michelle found the area of a circle as 78.5 . She used 3.14 for π. What is the radius of the circle? Explain how you found your
NikAS [45]

Answer:

5 units

Step-by-step explanation:

Given:-

- The area of the circle was computed to be A = 78.5

- The value of π is estimated to be = 3.14

Find:-

What is the radius of the circle?

Solution:-

- The area of a circle (A) with radius ( r ) is computed by the following formula:

                            A = π*r^2

- Divide the equation by π :

                            r^2 = ( A / π )

- Take the square root of the entire equation:

                            r = √ ( A / π )

- Substitute the given values:

                           r = √ ( 78.5 / 3.14 )

- Resolve the fraction:

                          r = √25

- The perfect square root of 25

                         r = 5

Answer: The radius of the circle is r = 5 units

                         

3 0
3 years ago
Read 2 more answers
The area model below shows a way to solve 7,776 ÷ 24 using place value. The 3 partial quotients missing from the model represent
Burka [1]

Answer: The answer is 324 all you have to do is just divide 7,776 by 24 then Breaking it into expanded form.

8 0
2 years ago
as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets
yKpoI14uk [10]

<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

  • parent-teacher conference = $35.50
  • school related assembly = $42
  • The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

<h3>Equations</h3><h3>x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)</h3>

From equation (i)

x+y  = 27\\x = 27-y...equation(iii)\\

Put equation(iii) into equation (ii)

35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5

Put y = 5 into equation 1

x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

brainly.com/question/4074386

8 0
3 years ago
Read 2 more answers
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