Answer:
18, -3
using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2
Answer:
m = -5.3
Step-by-step explanation:
-39.75 = 7.5m
Divide both sides by 7.5 to get m alone
-39.75/7.5 = 7.5m/7.5
-5.3 = m
Hope this helps:)
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
Answer: r<-2
Step-by-step explanation:
-3(r-5)+7>28
-3(r-5)+7-7>28-7
-3(r-5)>21
3(r-5)/3 < -21/3
r-5<-7
r-5+5<-7+5
r<-2
<span>your answer is C</span><span>
x + 55 = 4.2</span>
