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PilotLPTM [1.2K]
3 years ago
9

What is 52000-53800=? Show work

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
   53800
 - 52000
-------------
      1800
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Match the inequality to the graph of its solution.
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The first graph is c. c - 7 < 3.
The second graph is a. c + 7 ≤ 3.
The third graph is b. c - 3 > 1.
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The daily high temperatures for two cities are measured for a month. The results are shown in the box plot.
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Answer:

Interquartile range

Step-by-step explanation:

Range = 32, 29

Median = -6, 3

Upper quatile = 2, 13

Interquartile range = 11, 23

==> Interquartile range has the greatest difference of 23-11 = 12

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A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
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-2(v - 2) = -3 – 2v​
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Answer:

no solution

Step-by-step explanation:

Given

- 2(v - 2) = - 3 - 2v ← distribute left side

- 2v + 4 = - 3 - 2v ( subtract 4 from both sides )

- 2v = - 7 - 2v ( add 2v to both sides )

0 = - 7 ← not possible

This indicates the equation has no solution

3 0
3 years ago
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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