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RUDIKE [14]
3 years ago
11

Simplify (4−b)(5b2+5b−4)

Mathematics
1 answer:
astraxan [27]3 years ago
4 0

Answer:15b^2-5b^3+24b-16

Step-by-step explanation:

(4-b)(5b^2+5b-4)

Open the brackets

20b^2+20b-16-5b^3-5b^2+4b

Collect like terms

20b^2-5b^2-5b^3+20b+4b-16

15b^2-5b^3+24b-16

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4/5 divided by 1/3 ??
DochEvi [55]

Answer:

2.4

Step-by-step explanation:

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3 years ago
Find the absolute value of complex number Z = 2+5
sasho [114]
The answer would be 7.
6 0
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Im stuck please help solve these equasions much appreciated
borishaifa [10]

Answer:

Volume :

=1/3 a^2h

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Hope this helps you out and is what you were looking for! ☺

7 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
SOMEONE PLEASE HELP ME WITH THIS QUESTION 2.5x - 3 = 2x - 2 <br>I don't get what x is equal to
Luda [366]

Answer:

2

Step-by-step explanation:

Use the property of equality :)

5 0
3 years ago
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