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kotykmax [81]
3 years ago
11

Name a capital letter that appears to have a parallel lines.

Mathematics
2 answers:
mariarad [96]3 years ago
7 0
The only capital letter that I know that has parallel lines is capitol H.
Hope I helped!
kotykmax [81]3 years ago
7 0
The answer might be H or A
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Can someone help me please?
algol13

Answer:

x= 17

Step-by-step explanation:

6x+12=3x+63

Solve :)

7 0
3 years ago
The sum of two complex numbers, where the real numbers do not equal zero, results in a sum of 34i. Which statement must be true
Ipatiy [6.2K]

Answer:

The complex numbers have opposite real numbers.

8 0
4 years ago
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
-9 + 1/4x - 6 - 1/8x
Deffense [45]

Answer:

Assuming you want me to simplify your answer, the answer to your question is x/8-15.

Step-by-step explanation:

Simplify each term by combining 1/4 and x, and then combine x and 1/8 to get -9+x/4-6-x/8. Subtract 6 from -9 for x/4-15-x/8. Write x/4 as a fraction with a CD (Common Denominator) by multiplying by 2/2. Write each expression with a CD of 8. Combine the numerators, subract x from x*2 by reordering x and 2 to get 2*x-x/8-15. Then subract x from x to get x/8-15.

5 0
3 years ago
Read 2 more answers
Write an equation for the line in slope-intercept form
choli [55]
Points: (0,4) and (2,-3)
Find slope: (-3-4)/(2) = -7/2
4 = -7/2(0) + b, b = 4
Equation: y = -7/2x + 4
4 0
3 years ago
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