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san4es73 [151]
3 years ago
7

What is the perimeter of triangle ABC round each step by the nearest 10th see image. Thanks so much

Mathematics
1 answer:
Greeley [361]3 years ago
5 0

Perimeter of the triangle ABC is 18.7 units.

Coordinate of the point A is (4, -1), B is (-1, 4) and C is (0, -3).

Length of the side AB = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

AB = \sqrt{(-1-4)^{2}+(4+1)^{2}} =\sqrt{50}

AB = 7.07 units = 7.1 units ( rounded to the nearest 10th)

Length of the side BC = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

BC = \sqrt{(0+1)^{2}+(-3-4)^{2}}

BC = \sqrt{50}

BC = 7.07 units = 7.1 units ( rounded to the nearest 10th)

Length of the side CA =\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

CA = \sqrt{(4-0)^{2}+(-1+3)^{2}}

CA = \sqrt{20}

CA = 4.47 units = 4.5 ( rounded to the nearest 10th)

Perimeter of the triangle ABC = sum of all three sides = (7.1 + 7.1 + 4.5) units = 18.7 units  

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