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Fiesta28 [93]
3 years ago
9

Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.

Mathematics
1 answer:
uysha [10]3 years ago
5 0
The first thing I'd do is put this equation into standard slope - intercept form. 

12x - 5y = 2               Subtract 12x from each side
-5y = -12x + 2            Divide each side by -5 to isolate the <em>y 
</em><em />y = 12/5(x) - 2/5    
     
 The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b                    Fill in the variables
3 = 12/5(2) + b             Simplify
3 = 24/5 + b                 Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer. 

y = 12/5x - 9/5
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###########################################################

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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I
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Answer:

Time = 11\frac{2}{3}\ min

Step-by-step explanation:

Given

Security\ A = 2\ mins, 20\ secs

Security\ B = 1\ mins, 40\ secs

Required

After how many minutes, will they round together

First, convert the given time to minutes

Security\ A = 2\ mins, 20\ secs

Security\ A = 2\ mins+ 20\ secs

Security\ A = 2\ mins+ \frac{20}{60}\ min

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Security\ B = 1\frac{2}{3}\ min

List out the multiples of the time of both security personnel take round.

Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...

Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...

In the above lists, the common time is:

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4 0
3 years ago
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