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3 years ago

9

Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.

1 answer:

uysha [10]3 years ago

5 0

The first thing I'd do is put this equation into standard slope - intercept form.

12x - 5y = 2 Subtract 12x from each side
-5y = -12x + 2 Divide each side by -5 to isolate the <em>y
</em><em />y = 12/5(x) - 2/5

The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b Fill in the variables
3 = 12/5(2) + b Simplify
3 = 24/5 + b Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer.

y = 12/5x - 9/5

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Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

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$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

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So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

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x = 7 , then

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