Question

Write the equation of the line that passes through (2, 3) and is parallel to the line 12x – 5y = 2.

Answer 1

The first thing I'd do is put this equation into standard slope - intercept form. 

12x - 5y = 2               Subtract 12x from each side
-5y = -12x + 2            Divide each side by -5 to isolate the y 
y = 12/5(x) - 2/5    
     
 The slope for this equation is 12/5, so we just take that and plug it into the slope - intercept equation with the given points (2, 3)

y = mx + b                    Fill in the variables
3 = 12/5(2) + b             Simplify
3 = 24/5 + b                 Subtract 24/5 (or 4 4/5) from each side
-9/5 = b

Now we just fill in the correct variables (m and b) in the equation to have our final answer. 

y = 12/5x - 9/5