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harina [27]
4 years ago
9

Can somebody help me out with explain this to me ?

Mathematics
1 answer:
Savatey [412]4 years ago
4 0
Answer:
angle LKJ = 49 degrees

Explanation:
Triangle JKL is a right-angled triangle. This means taht the special trigonometric functions can be applied.
These trig functions are:
sine θ = opposite side / hypotenuse
cos θ = adjacent side / hypotenuse
tan θ = opposite side / adjacent side

In the given:
θ is angle LKJ
the opposite side is LJ = 8.9 cm
the adjacent side is LK = 7.7 cm
using the tan of the angle:
tan (LKJ) = 8.9 / 7.7
angle LKJ = tan^-1 (8.9 / 7.7)
angle LKJ = 49.134 which is approximately 49 degrees

Hope this helps :)
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Step-by-step explanation: Hope this helps :)

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The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,
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The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

  • Part A: The starting point is in the second quadrant and the finishing point is in the fourth quadrant.
  • Part B: The starting point and the check point are on different quadrant. Both points are on the same horizontal line.

Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the <em>x</em> and <em>y</em>-values in the quadrants are;

  • \begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right]

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

coordinate is negative and the y-coordinate is positive, the quadrant of the

starting point is quadrant II (the second quadrant).

  • <u>The quadrant of the starting point is the second quadrant</u>.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

  • <u>The quadrant of the finishing point is the fourth quadrant</u>.

Part B: The location of the checkpoint is; (5.3, 1)

The difference is that the x-value of the checkpoint is positive while the x-value of the starting point is negative, and they are therefore on different quadrants.

The similarity is that, the magnitude of the <em>x</em>, and <em>y</em> values of the coordinates of the check point and the starting point are the same. Therefore, the checkpoint and the starting point are on <u>the same horizontal line</u>.

Learn more about the Cartesian coordinate plane here:

brainly.com/question/17877300

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