Answer:
Step-by-step explanation:
![3\log_5(x-10)-\dfrac{1}{2}\log_54=5\log_52\\\\\text{Domain:}\ x-10>0\to x>10\\\\\text{use}\\\\\log_ab^n=n\log_ab\\\\\log_ab-\log_ac=\log_a\left(\dfrac{b}{c}\right)\\========================\\\\\log_5(x-10)^3-\log_54^\frac{1}{2}=\log_52^5\qquad\text{use}\ a^\frac{1}{2}=\sqrt{a}\\\\\log_5(x-10)^3-\log_5\sqrt4=\log_532\\\\\log_5(x-10)^3-\log_52=\log_532\\\\\log_5\dfrac{(x-10)^3}{2}=\log_532\iff\dfrac{(x-10)^3}{2}=32\qquad\text{multiply both sides by 2}\\\\(x-10)^3=64\to x-10=\sqrt[3]{64}\\\\x-10=4\qquad\text{add 10 to both sides}\\\\x=14\in D](https://tex.z-dn.net/?f=3%5Clog_5%28x-10%29-%5Cdfrac%7B1%7D%7B2%7D%5Clog_54%3D5%5Clog_52%5C%5C%5C%5C%5Ctext%7BDomain%3A%7D%5C%20x-10%3E0%5Cto%20x%3E10%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%5C%5C%5C%5Clog_ab%5En%3Dn%5Clog_ab%5C%5C%5C%5C%5Clog_ab-%5Clog_ac%3D%5Clog_a%5Cleft%28%5Cdfrac%7Bb%7D%7Bc%7D%5Cright%29%5C%5C%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_54%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Clog_52%5E5%5Cqquad%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%7Ba%7D%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_5%5Csqrt4%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%28x-10%29%5E3-%5Clog_52%3D%5Clog_532%5C%5C%5C%5C%5Clog_5%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D%5Clog_532%5Ciff%5Cdfrac%7B%28x-10%29%5E3%7D%7B2%7D%3D32%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%202%7D%5C%5C%5C%5C%28x-10%29%5E3%3D64%5Cto%20x-10%3D%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5Cx-10%3D4%5Cqquad%5Ctext%7Badd%2010%20to%20both%20sides%7D%5C%5C%5C%5Cx%3D14%5Cin%20D)
Pythagorean Theory, a^2 + b^2 = c^2
24^2 + 7^2 = x^2
527 = x^2
x = 22.96
48.75 =7.5✖️w
48.75/7.5=w
6.5=w
Answer is w=6.5
I think???
Answer:
No
Step-by-step explanation:
Write the ratios of erasers to cost (dropping the dollar sign) as fractions:
(number of erasers)/(price): 2/1 and 10/4
The question is if the ratios 2/1 and 10/4 are equivalent.
2/1 = 2
10/4 = 2.5
A proportion is setting two ratios equal. Here, one ratio equals 2, and one ratio equals 2.5.
Since the ratios are not equivalent, the relation is not proportional.
