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3 years ago

How to master Algebra 1

Mathematics

2 answers:

Kobotan [32]3 years ago

6 0

D+ that is how i master algebra 1

VashaNatasha [74]3 years ago

4 0

Get a C once every two quarters and you’ll pass my guy

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Please help! It’s Saturday and I only have this question left on my digital worksheet!

Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

So we have

Using the rules of indices

So we have the final answer as

Hope this helps you

4 0

3 years ago

HURRY Which is an equation in point-slope form for the line that passes through the points (−1,4) and (3,−4) ?

mash [69]

Answer:

y-4=-2(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(-4-4)/(3-(-1))

m=-8/(3+1)

m=-8/4

m=-2

y-4=-2(x-(-1))

y-4=-2(x+1)

7 0

3 years ago

Can someone help me with this? PLs i'm so confused!

barxatty [35]

1. E. $sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

2. L. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

3. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}$

4. Y. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

5. W. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

6. $tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}$

7. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

8. W. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}$

9. I. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

10. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

11. E. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}$

12. I. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

13. U. $sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}$

14. I. $cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}$

15. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}$

16. R. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}$

17. M. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}$

18. N. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}$

19. L. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}$

20. H. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}$

21. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}$

22. O. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

23. O. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

24. N. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1$

7 0

3 years ago

If p(x)= 2x3+ a x2+ 3x–3 and f(x) = x3 + x2-4x+ aleave the same remainder when divided by x-2, find the value of a.

Luda [366]

Answer:

a = 3

Step-by-step explanation:

$p(x) = 2x^{3} + ax^{2} +3x -3\\f(x) = x^{3} + x^{2} - 4x + a$

To get the remainder when these polynomials are divided by x - 2, subsitute(x = 2) into both functions.

$p(2) = 2(2^{3}) + a(2^{2}) +(3*2) -3\\p(2) = 19 - 4a\\f(2) = 2^{3} + 2^{2} - (4*2) + a\\f(2) = 4 + a$

Since the remainders are the same, p(2) = f(2)

19 - 4a = 4 + a

19 - 4 = a + 4a

15 = 5a

a = 15/5

a = 3

6 0

3 years ago

Valerie and her parents are going to her grandparents' house in Tennessee. It is a 3-hour drive. If they leave at 9:00 am and do

prisoha [69]

Answer: 12:00 pm

Step-by-step explanation:

Valerie and her parents are goig to see her grandparents.

The grandparents leave 3 hours away.

They leave at 9:00 am.

The rime they'll arrive is therefore:

= 9 + 3 hours

= 12:00 pm

3 0

3 years ago