yhu aint funni fym im frum da h00d cri.pppp
Answer:
4.39 hundredths
Step-by-step explanation:
The volume of the gallon is 6000 gallon
the rate of water flow per min is f(t)=300t^2
a] amount of water that flowed in the first 7 minutes=7/60 hours will be:
f(7)=300(7/60)^2
solving the above we get
f(7)=7/12 gallons
b] The time taken for the tank to be empty will be as follows:
amount of water that will flow out for the tank to be empty will be 6000 gallons
thus,
6000=300t^2
this can be simplified to
20=t^2
t^2-20=0
solving this we get:
t=-2√5 or 2√5
the time taken for the tank to be empty will be t=2√5 hours=5.4721 hours
Answer:
Step-by-step explanation:
Check attachment for solution
The
<u>correct answer</u> is:
20/27 = 0.7407.
Explanation:
To find the probability that the restaurant buys at least 2 non-defective units, we find the probability that they purchase either 2 or 3 non-defective units:
They purchase <u>3 units total</u>, so this is <u>n</u>.
We want the <u>probability of either 2 or 3</u> non-defective units; this means <u>r is 2 and r is 3</u>.
In this case we want the probability that the units are non-defective. Since there are 4 defective units, this means there are 12-4=8 non-defective units; this makes the <u>probability of a non-defective unit 8/12 = 2/3. This is p</u>.
Using these, we have: