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dem82 [27]
3 years ago
8

Anais bought 3 1/2 yards of ribbon. She had 2 feet 10 inches of ribbon left after trimming some curtains. How many inches of rib

bon did Anais use to trim the curtains?
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0
First, convert how many yards there were to inches. 3 1/2 yards gets you 126 inches. Next, find out how many inches 2 feet and 10 inches of ribbon is. 34 is your answer. Subtract 34 from 126 to get an answer of 92 inches (7 feet, 6 inches.) 
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15 POINTS!!!!!! PLEASE HELP!!The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, wha
marin [14]
Here is the information we have:

1. The perimeter is at most 130 cm.
2. The length of the rectangle is 4 times the width.
    We can let l stand for length and w for width.

The formula for the perimeter of a rectangle is 2l + 2w.
We have to change the formula a bit.
The length of this rectangle is going to be 4 times the width
So, replace 2l with 2(4w).

Then make this equation equal to 130.

2(4w) + 2w = 130 ; Start
8w + 2w = 130      ; Distribute the 2 across the 4w
10w = 130             ; Combine the like terms 8w and 2w
w = 13                   ; Divide both sides by the coefficient of w. Which is 10

8 0
3 years ago
A store sells two different types of coffee beans; the more expensive one sells for $8 per pound, and the cheaper one sells for
dangina [55]
All u need to do is give branliest then i will answer your question
3 0
3 years ago
Students attending the University of Florida can select from 130 major areas of study. A student's major is identified in the re
omeli [17]

Answer:

1. 8385 double majors

2. 18252 major codes

3. 8515 codes

4. Yes

Step-by-step explanation:

Given

Major areas = 130

Alphabets = 26

a.

There are 130 major areas in the university.

To get a double majors, means one select any of two of the major areas in the university.

i.e. just 2 alphabets are needed

Number of Double Majors = 130C2

130C2 = 130!/(128!*2!)

130C2 = 130 * 129/2

130C2 = 8385.

b.

Number of major codes available = Number of 2 digit codes + Number of 3 digit codes

Number of 2 digit codes = 2 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

So, number of 2 digit codes = 26 * 26 = 676.

Number of 3 digit codes = 3 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

There are 26 ways of selecting the third letter

So, number of 3 digit codes = 26 * 26 * 26 = 17576

Thus, number of major codes = 17576 + 676 = 18252

c.

Number of codes to identify a student with either a single major or double major

Number off single major codes = number of major areas = 130

Number of double major codes = 8385

Total = 130 + 8385 = 8515

d. From the solutions above, Yes there are enough codes available to identify all single and double majors at the university

6 0
3 years ago
Find the value of y.
True [87]

Answer:

6

Step-by-step explanation:

6 0
2 years ago
7 * (-3) =<br> What Is the answer <br> This is multiplication
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Answer:

-21

Step-by-step explanation:

7 0
2 years ago
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