Question

Theodore needs to mix a 10% fungicide solution with a 50% fungicide solution to create 100 milliliters of a 26% solution. How many milliliters of each solution must Theodore use?

Answer 1

Answer:

Therefore  40 milliliter of 50% fungicide solution is required

Therfore  60 milliliter of 10% fungicide solution is required

Step-by-step explanation:

i) Let the 10% fungicide solution have x milliliter and the 50% fungicide solution have y milliliter.

ii) Therefore 10x + 50y = 26(x + y)

                      x + y = 100

iii) form the first equation in ii) we get

                   16 x  = 24 y   Therefore $x = \frac{24}{16} y = \frac{3}{2} y$

iv) substituting the value obtained in iii) in the second equation in ii) we get

      $\frac{3}{2} y + y = \frac{5}{2} y = 100$

  Therefore y = 100 ÷ 2.5 =  40 milliliter

   Therfore x = 100 - 40 = 60 milliliter