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goldenfox [79]
3 years ago
13

Help lol I don’t know what to do

Mathematics
2 answers:
aliina [53]3 years ago
6 0

Answer:B

Step-by-step explanation:

anyanavicka [17]3 years ago
3 0
<h3>Answer:  B) 4+2n = 8</h3>

=========================================

Explanation:

n = some unknown number

2n = twice a number

4+2n = four more than twice a number

4+2n = 8 since the "is" means "equals"

Below is a diagram showing the word problem broken up in a table form

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Let cos A = <img src="https://tex.z-dn.net/?f=1%2F%5Csqrt%7B10%7D" id="TexFormula1" title="1/\sqrt{10}" alt="1/\sqrt{10}" align=
Rzqust [24]
Umm i’m sorry but what is the question here .

This isn’t english
3 0
2 years ago
543.3 + 3..28 help me
Dahasolnce [82]

Answer:546.58

Because if u add it all together it gives u that answer

5 0
3 years ago
Read 2 more answers
If sinθ = -1/2 and θ is in Quadrant III, then tanθ = _____.
Gnom [1K]

Answer:  \tan \theta=\dfrac{1}{\sqrt3}.

Step-by-step explanation:  Given that

\sin\theta=-\dfrac{1}{2} and \theta lies in Quadrant III.

We are to find the value of \tan \theta.

We will be using the following trigonometric identities:

(i)~sin^2\theta+\cos^2\theta=1,\\\\(ii)~\dfrac{\sin\theta}{\cos{\theta}}=\tan \theta.

We have

\tan\theta\\\\\\=\dfrac{\sin\theta}{\cos\theta}\\\\\\=\dfrac{\sin\theta}{\pm\sqrt{1-\sin^2\theta}}\\\\\\=\pm\dfrac{-\frac{1}{2}}{\sqrt{1-\left(\frac{1}{2}\right)^2}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\sqrt{1-\frac{1}{4}}}\\\\\\=\pm\dfrac{\frac{1}{2}}{\frac{\sqrt3}{2}}\\\\\\=\pm\dfrac{1}{\sqrt3}.

Since \theta lies in Quadrant III, so tangent will be positive.

Thus,

\tan \theta=\dfrac{1}{\sqrt3}.

8 0
3 years ago
Read 2 more answers
I NEED THIS ASAP SOMEONE PLEASE HELP I WILL BRAINLIEST!!<br> PLEASE<br> PLEASE<br> PLEASE
hodyreva [135]

Answer:

B

Step-by-step explanation:

I believe that the answer to this question is B. I think this because I took 5.2 and divided it by 0.4 which gave me 13. I did 5.2 divided by 0.4 because it wanted to know how many times 0.4 goes into 5.2.

I hope this helps I am rlly srry if I am wrong. have a beautiful day.

7 0
2 years ago
Write an equation for the line that passes through (4,10) and is perpendicular to the line 6x-3y=5​
padilas [110]

Answer:

y =  -  \frac{ 5}{3} x + ( -  \frac{5}{3} )

Step-by-step explanation:

-3y=5-6x

y=5-6x÷(-3)

y=(-5/3)+2x

y=2x-(5/3)

At y-intercept x is 0 and y is -(5/3)

Gradient m=10-(-5/3)÷(4-0)

=35/12

y=mx+c

10=(35/12)4+c

c=-(5/3)

3 0
2 years ago
Read 2 more answers
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