Simplify sqrt 363 -3 sqrt 27

1 answer:

5 0

If you have 2 of the same factor in a square root you take them out but just write one.

Looking at $\sqrt{363}$
$\sqrt{363} = \sqrt{3*11*11} =11 \sqrt{3}$

Looking at $3 \sqrt{27}$
$3\sqrt{27}=3 \sqrt{3*3*3} = (3*3)\sqrt{3} =9 \sqrt{3}$

Put them back together:
$11 \sqrt{3} -9 \sqrt{3} =2 \sqrt{3}$

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Compare 7/8 and 5/6

Ganezh [65]

Answer:

7/8 > 5/6

Step-by-step explanation:

Well look at it this way: 7/8 needs 1 more eighth until 1. 5/6 needs one more sixth until one. One eighth is smaller, so it requires a smaller amount to get to a greater number, if that makes sense. So 7/8 is greater than 5/6.

4 0

2 years ago

I need this answer fast! Please!

vovangra [49]

Answer:

$\large\boxed{\begin{array}{c|c|c|c}Length:&4cm&2cm&8cm\\Width:&6cm&12cm&3cm\\Height:&9cm&9cm&9cm\end{array}}$

Step-by-step explanation:

The formula of a volume of a cube with side length a:

$V=a^3$

We have a = 6cm. Substitute:

$V=6^3=216\ cm^3$

$\begin{array}{c|c}216&2\\108&2\\54&2\\27&3\\9&3\\3&3\\1\end{array}$

$216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2)\cdot(2\cdot3)\cdot(3\cdot3)=4\cdot6\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=2\cdot(2\cdot2\cdot3)\cdot(3\cdot3)=2\cdot12\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2\cdot2)\cdot3\cdot(3\cdot3)=8\cdot3\cdot9\\\vdots$