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Margaret [11]
3 years ago
12

Simplify sqrt 363 -3 sqrt 27

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
If you have 2 of the same factor in a square root you take them out but just write one.

Looking at \sqrt{363}
\sqrt{363} = \sqrt{3*11*11} =11 \sqrt{3}

Looking at 3 \sqrt{27}
3\sqrt{27}=3 \sqrt{3*3*3}  = (3*3)\sqrt{3} =9 \sqrt{3}

Put them back together:
11 \sqrt{3} -9 \sqrt{3} =2 \sqrt{3}
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The remainder is 110 when f(x) = 2x^3-5x+ 2 is divided by x-4

Step-by-step explanation:

We need to find the remainder when f(x) = 2x^3-5x+ 2 is divided by x-4

Solving:

The solution is attached in the figure below.

The quotient is: 2x^2+8x+27

The remainder is: 110

Keywords: quotient, division

Learn more about Division and quotient at:

  • brainly.com/question/629998
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