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Margaret [11]
3 years ago
12

Simplify sqrt 363 -3 sqrt 27

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
If you have 2 of the same factor in a square root you take them out but just write one.

Looking at \sqrt{363}
\sqrt{363} = \sqrt{3*11*11} =11 \sqrt{3}

Looking at 3 \sqrt{27}
3\sqrt{27}=3 \sqrt{3*3*3}  = (3*3)\sqrt{3} =9 \sqrt{3}

Put them back together:
11 \sqrt{3} -9 \sqrt{3} =2 \sqrt{3}
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You increase the size of a page by 30%. Then you decrease it by 30%. What is the size of the page now?
kotegsom [21]
Lets use 1 to solve this problem because it is easiest to show. 

Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3). 

Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)  

Therefore the page had a 9% reduction from its original size or is 91% of its original size. 
8 0
3 years ago
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What is 2.16 repeated as a decimal
Zarrin [17]
Ok, so what we want to do here is first remove the repeating decimal.

x=2.16 repeating
10x=21.6 repeating
100x=216.6 repeating

Subtract 10x=21.6 repeating from 100x=216.6 repeating. This will get rid of the repeating numbers.

100x=216.6 repeating
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__________________
90x=195

Divide both sides by 90.

x=195/90

Now you can simplify that into 13/6.


5 0
3 years ago
Ms Adams shares out 36 pencils between Niamh and jack in the ratio 4:8
malfutka [58]

Answer:

Niamh gets 12 and Jack gets 24.

Step-by-step explanation:

4:8 is equal to 1:2. 1 part + 2 parts is equal to 3 parts, which is equal to the whole. 36 is the whole, so 36/3 is equal to 12. 1 * 12 is equal to 12, and 2 * 12 is equal to 24.

7 0
3 years ago
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I need help on this and the first person who answer correctly gets a BRANLIST​
Alborosie

Answer:

It would be D

Step-by-step explanation:

All the coordinates are divided by half.

6 0
3 years ago
Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.
klasskru [66]

Answer:

See the explanation

Step-by-step explanation:

We know that

f(x) = 2x⁶ + 3x⁴ - 4x³ + (1/x) - sin2x

Lets calculate the derivatives:

f'(x) = 6(2x⁵) + 4(3x³) - 3(4x²) -( 1/x²) - 2(cos2x)

f'(x) = 12x⁵ + 12x³ - 12x² - (1/x²) - 2cos2x

Similarly:

f''(x) = 60x⁴ + 36x² - 24x + (2/x³) + 4sin2x

f'''(x) = 240x³ + 72x - 24 - (6/x⁴) + 8cos2x

Rearrange:

f'''(x) - 240x³ +72x - (6/x⁴) + 8cos2x - 24

f''''(x) = 720x² + 72 + (24/x⁵) - 16sin2x

Rearrange:

f''''(x) = 720x² + (24/x⁵) - 16sin2x +72

8 0
3 years ago
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