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KatRina [158]
3 years ago
6

What is an expression for "Four subtracted from the quotient of X and 3

Mathematics
2 answers:
ololo11 [35]3 years ago
7 0
The quotient of x and 3 would be written as x/3. Then subtract 4 from that so...
\frac{x}{3} - 4
LUCKY_DIMON [66]3 years ago
4 0
" the quotient " means divide

(x/3) - 4 <== ur expression
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3/7 x =5/14<br> solve for X
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Answer:

\frac{5}{6} = x

Step-by-step explanation:

\frac{3}{7}x = \frac{5}{14} \\ \\ \frac{5}{14} \div \frac{3}{7} = \frac{5}{14} \times \frac{7}{3} = \frac{35}{42} = \frac{5}{6}

Use multiplication [inverse of division] to figure this out.

* 2⅓ = 7⁄3

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In the figure below, BCA ~ STR. Find cos C, sin C, and tan C. Round your answers to the nearest hundredth.
arsen [322]

Answer:

\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63

Step-by-step explanation:

According to the trigonometric ratios in aright triangle :

\sin x =\dfrac{\text{Side opposite to x}}{\text{Hypotenuse}}\\\\\cos x =\dfrac{\text{Side adjacent to x}}{\text{Hypotenuse}}\\\\\tan x=\dfrac{\sin x}{\cos x}

Given:  ΔBCA ~ ΔSTR

Since , corresponding angles of two similar triangles are equal.

So, ∠C = ∠T                            ...(i)    [Middle letter]

In triangle STR

\sin T=\dfrac{\text{Side opposite to T}}{\text{Hypotenuse}}\\\\=\dfrac{26.4}{30.9}\approx0.85\\\\\cos x =\dfrac{\text{Side adjacent to T}}{\text{Hypotenuse}}\\\\=\dfrac{16.2}{30.9}\approx0.52\\\\\tan T=\dfrac{\sin T}{\cos T}\\\\=\dfrac{0.85}{0.52}\approx1.63  ...(ii)

From (i) and (ii), we have

\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63

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