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3 years ago

What is an expression for "Four subtracted from the quotient of X and 3

Mathematics

2 answers:

ololo11 [35]3 years ago

7 0

The quotient of x and 3 would be written as x/3. Then subtract 4 from that so...
$\frac{x}{3} - 4$

LUCKY_DIMON [66]3 years ago

4 0

" the quotient " means divide

(x/3) - 4 <== ur expression

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3 years ago

2x+3y=4

garri49 [273]

Answer:

Option D.

Step-by-step explanation:

we have

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$2x-5y=-12$ -----> equation B

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$-1(2x+3y)=-1(4)$

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Adds equation C and equation B

$-2x-3y=-4\\2x-5y=-12\\------\\-3y-5y=-4-12\\-8y=-16\\y=2$

Find the value of x

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The solution is the point (-1,2)

In this problem Option A,B and C are correct

The option D not result in a system with a pair of opposite terms

because

Multiply both sides of equation B by -3

$-3(2x-5y)=-3(-12)$

$-6x+15y=36$ -----> equation C

Multiply both sides of equation A by 5 $5(2x+3y)=5(4)$

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equation C and equation D not have a pair of opposite terms

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3 years ago

LESSON 3.2 (C) - Rates of Change and Slope

frozen [14]

Answer:

1. Slope = -2

2. Slope = ⁴/3

3. Slope = -3

4. Slope = 1

Step-by-step explanation:

1. Using two points on the line, (0, 0) and (-1, 2):

$slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{2 - 0}{-1 - 0} = \frac{2}{-1} = -2$

2. Using two points on the line, (0, 0) and (3, 4):

$slope = \frac{y_2 - y_1}{x_2 - x1} = \frac{4 - 0}{3 - 0} = \frac{4}{3}$

3. Using two points on the line, (0, 0) and (-1, 3):

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4. Using two points on the line, (0, 0) and (2, 2):

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2 years ago