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Free_Kalibri [48]

3 years ago

8

Dan paid the grocery bill of $76.45 with $100. Mistakenly the cashier gave Dan only $13.55 in change. How much more does the cas

hier owe Dan?

2 answers:

ladessa [460]3 years ago

6 0

Another 10 dollars. $100.00-76.45= $23.55

ollegr [7]3 years ago

4 0

$10.00

100-76.45=23.55 23.55-13.55=10.

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Use structure find the perimeter of equilateral triangle klm given the vertices k(-2, 1) and m(10, 6).

Deffense [45]

Perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.

As given in the question,

Coordinates of vertices K(-2,1) and M(10,6)

KM = $\sqrt{ (10-(-2)^{2} +(6-1)^{2} }$

= $\sqrt{12^{2}+5^{2} }$

= 13units

In equilateral triangle KL = LM = KM = 13 units

Perimeter of equilateral triangle KLM = 13 +13 +13

= 39 units

Therefore, perimeter of the equilateral triangle KLM with vertices K(-2 ,1) and M (10,6) is equal to 39 units.

Learn more about perimeter here

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4 0

9 months ago

Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for

e-lub [12.9K]

Answer:

a) Hence the endpoints of a t-distribution with 5% beyond them in each tail if the sample has size n=12 is ± 1.796.

b) Hence the endpoints of a t-distribution with 1% beyond them in each tail if the sample has size n=20 is ± 2.539.

Step-by-step explanation:

Here the answer is given as follows,

5 0

2 years ago

Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14

adoni [48]

Let 2x – y = 3 ——— equation 1

Let x + 5y = 14 ——— equation 2

Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

• Put eqn 3 in eqn 2

(y + 3 / 2) + 5y = 14

6y = 14 – 3/2

6y = 25/2

y = 25/12

• put y = 25/12 in eqn 3

x = (25/12 + 3/2)

x = 43/12

4 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

chantal volunteered to bring 1 gallon of freshly squeezed orange juice to a picnic.the local grocery store sells 4-pound bags of

pochemuha

(128 oz) * (2 oranges)/(5 oz) * (1 bag)/(11.5 oranges) * $3.49/bag ≈ $15.54

Note that we have assumed 11.5 oranges per bag, and that partial bags are available.

If Chantal must buy whole bags of oranges, 5 bags will be needed and the cost will be $17.45.

6 0

3 years ago