Answer:
Time = 3secs
Max height = 56m
Step-by-step explanation:
Given the height reached by the rocket modeled by the equation;
h(x) = -5(x - 3)² + 56 where;
x is in seconds
The rocket velocity at its maximum height is zero.
Hence dh/dx = 0
dh/dx = 2(-5)(x-3)
dh/dx = -10(x-3)
Since dh/dx = 0
0 = -10(x-3)
0 = -10x + 30
10x = 30
x = 3secs
<em>Hence it takes 3 secs to reach the maximum height.</em>
Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;
Recall that:
h(x) = -5(x - 3)² + 56
If x = 3
h(3) = -5(3 - 3)² + 56
h(3) = 0 + 56
h(3) = 56
<em>Hence the maximum height that the rocket reaches is 56m</em>
Answer:
7x4=28 there
Step-by-step explanation:
Answer:
answer is last part 2ln[3].
Step-by-step explanation:
what you all need to do is put y = Ao/3 and then cancel Ao from both L.H.S. and R.H.S. and then take log on both the sides, open the log funciton....
The formula is 1/2 times base times height. So,your answer is B
Answer:
Step-by-step explanation:
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