Answer:
![AX = 1084.20](https://tex.z-dn.net/?f=AX%20%3D%201084.20)
![BX = 1270.69](https://tex.z-dn.net/?f=BX%20%3D%201270.69)
Step-by-step explanation:
See attachment for complete question
Let the position of the submarine be represented with X
Given
![AB = 1425](https://tex.z-dn.net/?f=AB%20%3D%201425)
![\angle A = 59^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20A%20%3D%2059%5E%7B%5Ccirc%7D)
![\angle B = 47^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20B%20%3D%2047%5E%7B%5Ccirc%7D)
First, we calculate angle at X.
![\angle X + \angle A + \angle B = 180](https://tex.z-dn.net/?f=%5Cangle%20X%20%2B%20%5Cangle%20A%20%2B%20%5Cangle%20B%20%3D%20180)
![\angle X + 59^{\circ} + 47^{\circ}= 180^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20X%20%2B%2059%5E%7B%5Ccirc%7D%20%2B%2047%5E%7B%5Ccirc%7D%3D%20180%5E%7B%5Ccirc%7D)
![\angle X = 180^{\circ} -59^{\circ} - 47^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20X%20%3D%20180%5E%7B%5Ccirc%7D%20-59%5E%7B%5Ccirc%7D%20-%2047%5E%7B%5Ccirc%7D)
![\angle X = 74^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20X%20%3D%2074%5E%7B%5Ccirc%7D)
Solving (a): Distance AX: The distance between ship A and the submarine
To do this, we apply sine formula which states
![\frac{a}{sin\ A} = \frac{b}{sin\ B} = \frac{c}{sin\ C}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bsin%5C%20A%7D%20%3D%20%5Cfrac%7Bb%7D%7Bsin%5C%20B%7D%20%3D%20%5Cfrac%7Bc%7D%7Bsin%5C%20C%7D)
In this case:
![\frac{AB}{sin\ X} = \frac{AX}{sin\ B}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7Bsin%5C%20X%7D%20%3D%20%5Cfrac%7BAX%7D%7Bsin%5C%20B%7D)
Substitute values for AB,
and ![\angle B](https://tex.z-dn.net/?f=%5Cangle%20B)
![\frac{1425}{sin(74^{\circ})} = \frac{AX}{sin(47^{\circ})}](https://tex.z-dn.net/?f=%5Cfrac%7B1425%7D%7Bsin%2874%5E%7B%5Ccirc%7D%29%7D%20%3D%20%5Cfrac%7BAX%7D%7Bsin%2847%5E%7B%5Ccirc%7D%29%7D)
Make AX the subject
![AX = \frac{1425}{sin(74^{\circ})} * sin(47^{\circ})](https://tex.z-dn.net/?f=AX%20%3D%20%5Cfrac%7B1425%7D%7Bsin%2874%5E%7B%5Ccirc%7D%29%7D%20%2A%20sin%2847%5E%7B%5Ccirc%7D%29)
![AX = \frac{1425}{0.9613} * 0.7314](https://tex.z-dn.net/?f=AX%20%3D%20%5Cfrac%7B1425%7D%7B0.9613%7D%20%2A%200.7314)
![AX = \frac{1425 * 0.7314}{0.9613}](https://tex.z-dn.net/?f=AX%20%3D%20%5Cfrac%7B1425%20%2A%200.7314%7D%7B0.9613%7D)
![AX = \frac{1042.245}{0.9613}](https://tex.z-dn.net/?f=AX%20%3D%20%5Cfrac%7B1042.245%7D%7B0.9613%7D)
![AX = 1084.20](https://tex.z-dn.net/?f=AX%20%3D%201084.20)
Solving (b): Distance BX: The distance between ship B and the submarine
To do this, we apply sine formula which states
In this case:
![\frac{AB}{sin\ X} = \frac{BX}{sin\ A}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7Bsin%5C%20X%7D%20%3D%20%5Cfrac%7BBX%7D%7Bsin%5C%20A%7D)
Substitute values for AB,
and ![\angle A](https://tex.z-dn.net/?f=%5Cangle%20A)
![\frac{1425}{sin(74^{\circ})} = \frac{BX}{sin(59^{\circ})}](https://tex.z-dn.net/?f=%5Cfrac%7B1425%7D%7Bsin%2874%5E%7B%5Ccirc%7D%29%7D%20%3D%20%5Cfrac%7BBX%7D%7Bsin%2859%5E%7B%5Ccirc%7D%29%7D)
Make BX the subject
![BX = \frac{1425}{sin(74^{\circ})} * sin(59^{\circ})](https://tex.z-dn.net/?f=BX%20%3D%20%5Cfrac%7B1425%7D%7Bsin%2874%5E%7B%5Ccirc%7D%29%7D%20%2A%20sin%2859%5E%7B%5Ccirc%7D%29)
![BX = \frac{1425}{0.9613} * 0.8572](https://tex.z-dn.net/?f=BX%20%3D%20%5Cfrac%7B1425%7D%7B0.9613%7D%20%2A%200.8572)
![BX = \frac{1425* 0.8572}{0.9613}](https://tex.z-dn.net/?f=BX%20%3D%20%5Cfrac%7B1425%2A%200.8572%7D%7B0.9613%7D)
![BX = \frac{1221.51}{0.9613}](https://tex.z-dn.net/?f=BX%20%3D%20%5Cfrac%7B1221.51%7D%7B0.9613%7D)
![BX = 1270.69](https://tex.z-dn.net/?f=BX%20%3D%201270.69)
PP = 2L + 2W. Here, PP = 2(7 inches) + 2(5 inches) = 24 inches.
8=2x+4 ... 8-4=2x... 2x=4.. x=2
Answer:
Step-by-step explanation:
I think that 4733
I think 111 is the answer