Rewrite with only sin x and cos x.

Is -120/6 infinite or finite? is 2/10 infinite or finite?

Leona [35]

they are both finite because 2/10=0.2, and 0.2 doesn't go on forever. -120/6=-20, which also has an end, and doesn't go on forever. I hope this helps :)

7 0

4 years ago

An angle measure of 55.45 is converted to DMS notation as

jek_recluse [69]

Converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

Step-by-step explanation:

We need to convert angle measure of 55.45 to DMS notation

DMS notation is Degree Minute and seconds

Solving:

We have 55.45, the value before decimal is considered as degrees and values after decimal can be minutes and seconds.

We can write it as 55 and 0.45

So, we have 55 degrees

To find minutes we will multiply 0.45 by 60

0.45*60 = 27 minutes

Since we have no decimal value in minutes so seconds will be 0

So, DMS will be 55 degrees 27 minutes 0 seconds

Hence converting angle measure of 55.45 to DMS notation we get 55 degrees 27 minutes 0 seconds

5 0

3 years ago

-3/4(8n+12)=3(n-3) show work pls

Nastasia [14]

Answer: n = 0

Step-by-step explanation:

Given expression

(-3/4) (8n + 12) = 3 (n - 3)

Expand parentheses and apply the distributive property

-6n - 9 = 3n - 9

Add 9 on both sides

-6n - 9 + 9 = 3n - 9 + 9

-6n = 3n

Subtract 3n on both sides

-6n - 3n = 3n - 3n

-9n = 0

Divide -9 on both sides

-9n / -9 = 0 / -9

$\boxed{n=0}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

Find the mean of 1.8,1.7,1.3,1.1,1.2,1.6,1.8

Tpy6a [65]

Answer:

1.5

Step-by-step explanation:

To find the mean, we must add all of our terms, and then divide by the number of terms.

$1.8+1.7+1.3+1.1+1.2+1.6+1.8$

Solve:

$1.8+1.7+1.3+1.1+1.2+1.6+1.8=10.5$

Since we have seven terms, we must divide our total ( $10.5$ ), by seven.

$10.5$ ÷ $7$

Solve:

$10.5$ ÷ $7=1.5$

Therefore, the mean is $1.5$

8 0

4 years ago

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