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suter [353]
3 years ago
7

Which pair of words describes this system ?

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

consistent and dependent

Step-by-step explanation:

because are the same equation

k(y)=k(3x+2)

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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)= 7,u'(0)=-5,v(0)= -1, v'(0)= -4.
andriy [413]

This question is incomplete, the complete question is;

Suppose u and v are functions of x that are differentiable at x=0

and that { u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

Find the values of the following derivatives at x = 0.

a) \frac{d}{dx}( uv )

b)  \frac{d}{dx}( \frac{u}{v} )

c)  \frac{d}{dx}( \frac{v}{u} )

Answer:

a) \frac{d}{dx}( uv ) = -23  

b) \frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

Step-by-step explanation:

Given that;

{ u(0) = 7, u'(0) = -5 }  { v(0)= -1, v'(0) = -4 }

a)

\frac{d}{dx}( uv )

we differentiate

\frac{d}{dx}( uv )  = uv' + vu'

at x = (0), we substitute our values

\frac{d}{dx}( uv ) = ( 7 × -4 ) + ( -1 × -5)

\frac{d}{dx}( uv )  = -28 + 5

\frac{d}{dx}( uv ) = -23  

b)

\frac{d}{dx}( \frac{u}{v} )

we differentiate

\frac{d}{dx}( \frac{u}{v} ) = ( vu' - uv' ) / v²

at x=0, we substitute our values

\frac{d}{dx}( \frac{u}{v} ) = ( (-1 × -5) - (7 × -4 ) ) / (-1)²

\frac{d}{dx}( \frac{u}{v} ) = (( 5 - ( -28 )) / 1

\frac{d}{dx}( \frac{u}{v} )  = 33 / 1

\frac{d}{dx}( \frac{u}{v} )  = 33

c) \frac{d}{dx}( \frac{v}{u} )

we differentiate

\frac{d}{dx}( \frac{v}{u} )  = ( uv' - vu' ) / u²

at x=0, we substitute our values

\frac{d}{dx}( \frac{v}{u} )  = ( (7 × -4) - (-1 × -4) ) / (7)²

\frac{d}{dx}( \frac{v}{u} ) = ( -28 - ( 4 ) ) / 49

\frac{d}{dx}( \frac{v}{u} )  = ( -28 - 4 ) /49

\frac{d}{dx}( \frac{v}{u} )  = -32 / 49

\frac{d}{dx}( \frac{v}{u} ) = -32/49 or - 0.6531

6 0
3 years ago
Simplify the following expression and then write down the coefficient of x²: x² + x² + x² + x²
lapo4ka [179]

Answer:

The expression is 4x² and coefficient is 4.

Step-by-step explanation:

All have the same variables, x², so you add up together :

1{x}^{2}  +  1{x}^{2}  +  1{x}^{2}  +  1{x}^{2}

= 4 {x}^{2}

7 0
3 years ago
What is the 37th term of the arithmetic sequence with the first term -39 and the common difference of 8.
Mrrafil [7]

Answer:

a_{37}=249

Step-by-step explanation:

A sequence that has a common difference is an <em>arithmetic sequence</em>:

a_n=a_1+(n-1)d

where aₙ is the nth term, n is the index, and d is the common difference.

In your question:

  • n = 37
  • a₁ = -39
  • d = 8

Plug those into the formula:

a_{37}=-39+(37-1)8

Then solve:

a_{37}=-39+(36)8\\a_{37}=-39+288\\a_{37}=249

8 0
3 years ago
Students in Mr. Rivas’ class were practicing their multiplication skills by rolling three 6-sided number cubes. Chris rolled a 2
guajiro [1.7K]

Sorry wrote down the wrong thing the first time. Try doing 2 plus 3 times 5.

3 0
3 years ago
Read 2 more answers
Points R, S, and T are collinear, and S is between R and T. Find ST if RS = 6.4in and RT = 9.3 in.
babymother [125]

Answer:

Step-by-step explanation:

The layout looks like this.

r-----------s-----------------t

    6.4        

----------------9.3-----------

Now you want st so the formula is

rt = rs + st

9.3 = 6.4 + st            Subtract 6.4 from both sides

9.3 - 6.4 = st             Combine

st = 2.9

4 0
3 years ago
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