What is the question here? There’s multiple answers
Scientific method includes some steps that are necessary for conducting the successful experiment.
1. Make an observation
You observe the growth of the plant under the influence of light (phototropic effect) and you notice that some plants successfully grow under artificial light. You want to compare that growth with growth under the sunlight.
2. Ask a question
How does the light influence plant growth?
Are the wavelengths of the light important?
Is natural light source (sun) better for plant growth...
3. Form a hypothesis - it is a testable potential answer to the question
For example: Sunlight induces higher phototropic reaction.
4. Make a prediction
Sunlight is richer in red and blue hues which are both extremely important to plant growth.
5. Test the prediction
Design an experiment by putting one pot with beans outside on sunlight and other under the light bulb. Other conditions such as water must be the same. Monitor their growth for about 2 weeks and measure the results.
6. Analyze the data and make a conclusion.
A nucleotide is an organic molecule that is the building block of DNA and RNA. ... A nucleotide is made up of three parts: a phosphate group, a 5-carbon sugar, and a nitrogenous base. The four nitrogenous bases in DNA are adenine, cytosine, guanine, and thymine. RNA contains uracil, instead of thymine.
Hopefully this helped! :D
-LavenderVye
Answer/Explanation:
For the woman to be blood type B, she must either have 2 B alleles (homozygous, BB) or 1 B allele (heterozygous, BO). We can draw two punnett squares to show each of the potential outcomes when she has children with an AB man.
The two punnett squares are attached. In order to have a child that is type A, she needs to be heterozygous, BO. Even then, there was only a 25% chance that their child would have type A blood. If she were homozygous BB, it would be impossible for her to have a type A child with an AB man.
Answer:
pyruvate
Explanation:
Pyruvate, the product of glycolysis, is converted to acetyl-CoA, the starting material for the citric acid cycle, by the pyruvate dehydrogenase complex. Acetyl-CoA donates its acetyl group to the four-carbon compound oxaloacetate to form the six-carbon citrate.