9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
x ∉ R
Step-by-step explanation:
x² = - 21
if x² < 0 => x ∉ R
Answer:
D) {11,-4,-29}
Step-by-step explanation:
rewrite the equation as y= -5x+1 and plug in -2,1 and 6 to get y
-5*-2+1=11
-5*1+1=-4
-5*6+1=-29
Answer:
actually its depend on how is he working day by day
