<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>
Answer:
5.00
Step-by-step explanation:
answer
Answer:the balance after 7 years is $3216
Step-by-step explanation:
A) Initial amount deposited into the account is $2800 This means that the principal,
P = 2800
It was compounded yearly. This means that it was compounded once in a year. So
n = 1
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for 7 years. So
t = 7
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. Therefore
A = 2800(1 + 0.04/2)^ 1× 7
A = 2800(1 + 0.02)^7
A = 2800(1.02)^7
A = $3216
Answer:
a. 2^(x-2) = g^(-1)(x)
b. A, B, D
Step-by-step explanation:
the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)
1. replace g(x) with y and solve for x
y = log₂(x) + 2
subtract 2 from both sides to isolate the x and its log
y - 2 = log₂(x)
this text is replaced by the second image -- it was marked as inappropriate
thus, 2^(y-2) = x
replace x with g^(-1)(x) and y with x
2^(x-2) = g^(-1)(x)
2. plug this in to points A, B, C, D, E, and F
A: (2,1)
plug 2 in for x
2^(2-2) = 2⁰ = 1 so this works
B: (4, 4)
2^(4-2) = 2²= 4 so this works
C: (9, 3)
2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work
(5, 8)
2^(5-2) = 2³ = 8 so this works
E: (3, 5)
2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work
F: (8, 5)
2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work
Answer:
The Acceleration, In Centimeters Per Second Per Second, Of A Projectile Is Modeled By A (T) = 21" - 156 + 36, Where T Is Measured in seconds