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AlladinOne [14]
3 years ago
10

Simplify 1/2/5 please.

Mathematics
2 answers:
Setler [38]3 years ago
8 0

Answer:

0.1

Step-by-step explanation:

(1/2)/5 = 0.1

Mrac [35]3 years ago
4 0

Answer:

Step-by-step explanation:

1/2 x 1/5 = 1/10

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Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
3 years ago
Graph <br> What is the slope of the line?
maksim [4K]

Answer:

there is no graph

:( sorry I would answer it if it had a graph

6 0
4 years ago
1. You are going to rent a moped for $20 plus $2 an hour.
kondaur [170]
5x2=10
10+20=30
30 is the answer.
8 0
3 years ago
Read 2 more answers
Ab=6cm Ac=12 calculate the lenght of cd
Alchen [17]

This problem involves the uses of the Pythagorean Theorem as well as the use of Sine.

To start we need to identify what we know and what we don't know. We know that there are two triangles. We are given 2 sides lengths and an angle in one and only an angle in the other. They share one side meaning when we are given 2 sides in one triangle it will be easy to get the third side. What we don't know is the side length of CB DB or CD. We need to find CB in order to find CD.

<em>Pythagorean Theorem for side length CB:</em>

12^2-6^2=√108

√108=10.4 (average)

So CB is equal to 10.4

<em>Sine Calculation for side length CD:</em>

Since we have angle 56* we will use the length we found which will be the opposite side from the angle and then input x for our hypotenuse CD in order to solve.

sin 56* = 10.4/x

sin 56* × x = 10.4/x × x

sin 56*x = 10.4

/sin 56*      /sin 56*

x = 12.544....

or 12.6 (average)

So, to conclude, our answer for CD is 12.6cm.

Hope I helped!

7 0
3 years ago
Read 2 more answers
The height of a parallelogram is 6.5 cm.
o-na [289]

Area of parallelogram = base × height

Area = 6.5 × 13 = 84.5 cm²

8 0
4 years ago
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