Answer:
9.2*10^3
Step-by-step explanation:
to find the quotient you need to divide those numbers
8.832*10^6 / 9.6*10^2
= 8.832*10^4 / 9.6
= 0.92*10^4
= 9.2*10^-1+4
= 9.2*10^3
Answer:
Negative 3 plus:) hope this helps!
Answer:
y-4=-3/4(x+5)
Step-by-step explanation:
y-y1=m(x-x1)
y-4=-3/4(x-(-5))
y-4=-3/4(x+5)
I= PRT
I= 1400 X 0.015 X 0.5
I= 21 X 0.5
I= 10.5
if it was a full 12 months it would be
21 x 1= 21
if it was 1/5 years it would be
21 x 1.5 = 31.5 and so on
Answer:
0.8554 is the probability that the proportion of students living in dormitories is between 0.70 and 0.85
Step-by-step explanation:
We are given the following in the question:
Proportion of students who live in dormitories = 80%
![p= 0.80](https://tex.z-dn.net/?f=p%3D%200.80)
Sample size, n = 80
Thus, the number of students follow a binomial distribution,
We use normal approximation to the binomial distribution to find the probability.
Parameters of Normal distribution:
![\mu = np = 80\times 0.80 = 64\\\sigma = \sqrt{np(1-p)} = \sqrt{80(0.80)(1-0.80)} = 3.58](https://tex.z-dn.net/?f=%5Cmu%20%3D%20np%20%3D%2080%5Ctimes%200.80%20%3D%2064%5C%5C%5Csigma%20%3D%20%5Csqrt%7Bnp%281-p%29%7D%20%3D%20%5Csqrt%7B80%280.80%29%281-0.80%29%7D%20%3D%203.58)
We have to find the probability that the sample proportion (the proportion living in the dormitories) is between 0.70 and 0.85.
![P(0.70\leq p \leq 0.85)\\\\=P(0.70(80)\leq x \leq0.85(80))\\\\=P(56 \leq x \leq 68) \\\\= P(\displaystyle\frac{56 - 64}{3.58} \leq z \leq \displaystyle\frac{68-64}{3.58})\\\\ = P(-2.2346 \leq z \leq 1.1173)\\\\= P(z \leq 1.1173) - P(z < -2.2346)\\\\= 0.8681 - 0.0127 = 0.8554](https://tex.z-dn.net/?f=P%280.70%5Cleq%20p%20%5Cleq%200.85%29%5C%5C%5C%5C%3DP%280.70%2880%29%5Cleq%20x%20%5Cleq0.85%2880%29%29%5C%5C%5C%5C%3DP%2856%20%5Cleq%20x%20%5Cleq%2068%29%20%5C%5C%5C%5C%3D%20P%28%5Cdisplaystyle%5Cfrac%7B56%20-%2064%7D%7B3.58%7D%20%5Cleq%20z%20%5Cleq%20%5Cdisplaystyle%5Cfrac%7B68-64%7D%7B3.58%7D%29%5C%5C%5C%5C%20%3D%20P%28-2.2346%20%5Cleq%20z%20%5Cleq%201.1173%29%5C%5C%5C%5C%3D%20P%28z%20%5Cleq%201.1173%29%20-%20P%28z%20%3C%20-2.2346%29%5C%5C%5C%5C%3D%200.8681%20-%200.0127%20%3D%200.8554)
Thus, 0.8554 is the probability that the proportion of students living in dormitories is between 0.70 and 0.85