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3 years ago

It's not possible to build a triangle with side lengths of 3, 3, and 9.

Mathematics

2 answers:

Stels [109]3 years ago

5 0

Answer:B false

Step-by-step explanation:One side length can be different as long as it’s not an equilateral triangle.

Anton [14]3 years ago

4 0

Answer:

false

Step-by-step explanation:

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3(x + 1)² = 12 Solve for x.

vichka [17]

Answer:

x=1, -3

Step-by-step explanation:

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3 years ago

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Choose the TRUE statements.

Shalnov [3]

Answer:

The absolute value of a number 35 units to the left of zero on a number line is 35.

The absolute value of a number 12 units to the left of zero on a number line is 12.

The absolute value of a number 125 units to the right of zero on a number line is 125.by-step explanation:

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3 years ago

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Problem:

lorasvet [3.4K]

Answer:

The answer is: y = 9.25x 

Step-by-step explanation:

Let the equation for the proportionality relation is y = mx .......... (1), where y represents the money that Craig earns for a duty of x hours.

Here, m is the constant of proportionality and we have to find its value.

Given that Craig earns $37 for 4 hours duty.

So, from equation (1), we have 37 = 4m, ⇒ m = 9.25

Therefore, the equation becomes y = 9.25x. (Answer)

4 0

3 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

3 years ago

Is the ordered pair (4, 12) a solution to the equation y = 3x? If yes, is it the only solution? A. No, the ordered pair does not

uranmaximum [27]

Yes. 12=3(4). But it's not the only solution. The graph of the equation is a line, on which each of the infinite number of points is a solution to the equation. A few others are: (1,3), (2,6), (3,9), (19,57), (613, 1839), etc.

4 0

4 years ago