The equation to this problem would be y = x/2 + 1
2x° + 1 + x° - 6 + 59°= 360°
3x° + 54° = 360°
3x = 306°
x = 102°
2(102°) + 1°= 204° + 1° = 205°
102° - 6°= 96°
205° + 96° + 59°= 360°
Answer:
D. 264°
Step-by-step explanation:
When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,
60° = 1/2[(18x - 6)° - (5x +17)°]
60° * 2 = (18x - 6 - 5x - 17)°
120° = (13x - 23)°
120 = 13x - 23
120 + 23 = 13x
143 = 13x
143/13 = x
11 = x
x = 11
(18x - 6)° = (18*11-6)°= (198 - 6)° = 192°
(5x +17)° = (5*11 +17)° =(55+17)° = 72°
m (arc KNL) = (18x - 6)° + (5x +17)° = 192° + 72°
m (arc KNL) = 264°
Answer:
-42
Step-by-step explanation:
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Answer:
= 2
= k(k+1)
= (k+1)(k+2)
Step-by-step explanation:
We are given the statement,
as 2 + 4 + 6 + . . . + 2n = n(n+1)
That is,
as 2 + 4 + 6 + . . . + 2n = 
So, we have,
= 
= 2
= 
= 2 + 4 + 6 + . . . + 2k = k(k+1)
= = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)
Thus, we get,
= 2
= k(k+1)
= (k+1)(k+2)
