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3 years ago

8

The diameter of the circle is 24m.Tim incorrectly says that the circumference of the circle is about 37.68 m.What is the circumf

erence of the circle. What mistake did Tim make

1 answer:

Alja [10]3 years ago

4 0

If the diameter is 24 then you multiply that by pi to get the circumference

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Michael's babysitting is 20 years old. Michael is 8 years old. How much older is his babysitter than Micheal?

iogann1982 [59]

Answer:

12 years

Step-by-step explanation:

20-8=12

Micheal's babysitter is 12 years older than Micheal.

8 0

3 years ago

Michael boards an elevator at the 23rd floor. She travels up 14 floors, and then down 7 floors.

dem82 [27]

Michael will end up on the 30th floor.

7 0

3 years ago

A rectangular poster is to contain 882 square inches of print. The margins at the top and bottom of the poster are to be 2 inche

Zinaida [17]

Answer:

L = 23 in

h = 46 in

Step-by-step explanation:

Let call " x " and " y " dimensions of the print area of the poster then:

882 = x*y and y = 882/x

We also know that dimensions of the poster is:

L = x + 2 in and h = y + 4 in

Therefore area of the poster is:

A(p) = ( x + 2 ) * ( y + 4 ) And area as function of x is:

A(x) = ( x + 2 ) * ( 882/x + 4 )

A(x) = 882 + 4*x + 1764 /x + 8

Taking derivatives on both sides of the equation we have:

A´(x) = 4 - 1764/x²

A´(x) = 0 ⇒ 4 - 1764/x² = 0 ⇒ 4*x² - 1764 = 0

x² = 1764 / 4

x² = 441

x = 21 in and y = 882/x y = 42

The second derivative A´´(x) is > 0 ( the second term changes its sign to +) there is a minimum for the function at the point x = 21

As x and y are dimensions of the printing area of the poster, dimensions of the poster are

L = x + 2 = 21 + 2 = 23 in and

h = y + 4 = 42 + 4 = 46 in

4 0

4 years ago

The distance between bases on a baseball field is 90 feet.If 3 players hit home runs during a game and each runs around all 4 ba

m_a_m_a [10]

Well, think about it... 90 feet times 4 bases= 360 feet.. 360 feet times 3 players= 1080 feet

5 0

3 years ago

Tentukan persamaan garis yang di wakili ruas garis AB,BC,CD dan AD! <br>tolong kak

Ann [662]

Answers:

1. AB: y = - 2x - 6

2. BC: y = x - 3

3. CD: x = 3

4. AD: y = (3/7) x +26/7

Solution:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

1. AB

A=(-4,2)=(xa, ya)→xa=-4, ya=2

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

mab=(yb-ya)/(xb-xa)

mab=(-4-2)/(-1-(-4))

mab=(-6)/(-1+4)

mab=(-6)/(3)

mab=-2

y-ya=mab (x-xa)

y-2=-2(x-(-4))

y-2=-2(x+4)

y-2=-2x-8

y-2+2=-2x-8+2

y=-2x-6

2. BC

B=(-1,-4)=(xb, yb)→xb=-1, yb=-4

C=(3,0)=(xc, yc)→xc=3, yc=0

mbc=(yc-yb)/(xc-xb)

mbc=(0-(-4))/(3-(-1))

mbc=(0+4)/(3+1)

mbc=(4)/(4)

mbc=1

y-yc=mbc (x-xc)

y-0=1 (x-3)

y=x-3

3. CD

C=(3,0)=(xc, yc)→xc=3, yc=0

D=(3,5)=(xd, yd)→xd=3, yd=5

mcd=(yd-yc)/(xd-xc)

mcd=(-4-0)/(3-3)

mcd=(-4)/(0)

mcd= Infinite (Vertical line)

Equation vertical line: x=xc=xd

x=3

4. AD

A=(-4,2)=(xa, ya)→xa=-4, ya=2

D=(3,5)=(xd, yd)→xd=3, yd=5

mad=(yd-ya)/(xd-xa)

mad=(5-2)/(3-(-4))

mad=(3)/(3+4)

mad=3/7

y-ya=mad (x-xa)

y-2=(3/7)(x-(-4))

y-2=(3/7)(x+4)

y-2=(3/7)x+12/7

y-2+2=(3/7)x+12/7+2

y=(3/7)x+(12+7(2))/7

y=(3/7)x+(12+14)/7

y=(3/7)x+26/7

8 0

3 years ago