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Anestetic [448]
3 years ago
6

If , then line segment is parallel to line segment .

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
9 0

Answer:

its de=fg

Step-by-step explanation:

Lelechka [254]3 years ago
3 0
I need more info to be able to answer
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Leroy's total job benefits were $50,150 last year. His total job expenses for traveling and for professional developement for th
kykrilka [37]

Answer:

A. $46,650

Step-by-step explanation:

Taking the first number of $50,150, we have to subtract his expenses. After subtracting Leroy's expenses, we get $46,650.

  50150

<u>-    3500</u>

  46650

7 0
3 years ago
Read 2 more answers
Write the function in vertex form, and identify its vertex. g(x) = 5x2 - 50x + 128
steposvetlana [31]
Hello : 
<span>g(x) = 5x² - 50x + 128    
       = 5(x²-10x +128/5)
       = 5 (x²-10x+5²-5² +128/5)
        = 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
3 0
3 years ago
What is the value of f(5.3) f(x)=6[x] f(5.3)=
Kamila [148]
the value for f(5.3)=6×5.3
=31.8
7 0
3 years ago
. Trisha walked 9/10 of a mile to school. Write the decimal to show<br> how far Trisha walked.
Mandarinka [93]

Answer:

.9

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do I solve for x here? Use the properties of logarithms to find a value for x. Assume a,b, and M are constants.
Leona [35]

Yes, you're right! The first step is rewriting the equation as

\ln(a) + \ln(b^x) = M

Subtract \ln(a) from both sides:

\ln(b^x) = M-\ln(a)

Use the property \ln(a^b) = b\ln(a) to rewrite the equation as

x\ln(b) = M-\ln(a)

Divide both sides by \ln(b)

x = \dfrac{M-\ln(a)}{\ln(b)}

Alternative strategy:

Consider both sides as exponents of e:

e^{\ln(ab^x)} = e^M

Use e^{\ln(x)} = x to write

ab^x = e^M

Divide both sides by a:

b^x = \dfrac{e^M}{a}

Consider the logarithm base b of both sides:

x = \log_b\left(\dfrac{e^M}{a}\right)

The two numbers are the same: you can check it using the rule for changing the base of logarithms

7 0
3 years ago
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