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Vaselesa [24]
4 years ago
11

3. Students in a sixth-grade class were asked which team was their favorite. The results are shown in the table. Find the ratio

of students who preferred the Buccaneers to the total number of responses.
Mathematics
1 answer:
bulgar [2K]4 years ago
6 0
Not enough info to find the ratio
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Hello all I got stuck on this help please
steposvetlana [31]
45 because the right side of the triangle is 9 so the left side is too
5 0
3 years ago
Planet X is 8 1/5 light-years away from Earth. Planet Y is 2 3/5 light-years away from Earth.
Law Incorporation [45]

Based on the distance of Planet X from Earth and the distance of Planet Y, Planet X is 5 ³/₅ light-years farther away.

<h3>How much farther is Planet X from Earth?</h3>

To find how out how much farther planet X is from Planet Earth than Planet Y, subtract the distances:

Solving gives:

= 8 ¹/₅ - 2 ³/₅

= 41/5 - 13 / 5

= 28/5

= 5 ³/₅ light-years

Find out more on light-year distance at brainly.com/question/76984

#SPJ1

4 0
1 year ago
Solve the equation A = P + Prt for r. Solve the equation A = P + prt for p.
SCORPION-xisa [38]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo
NNADVOKAT [17]

Answer:

a

  P(a | e') =  0.22

  P(b | e') =  0.28

  P(c | e') =  0.33

b

  P(a | e' , d' , b') = 0.57

Step-by-step explanation:

From the question we are told that

   The probabilities are

Supplier  chosen            A                     B                    C            

Probability                P(a) = 0.20       P(b) =  0.25   P(c) =  0.15      

                                       D                      E

                                P(d) =  0.30     P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(a | e') =  \frac{P (a \  and \  e')}{P(e')}

      P(a | e') =  \frac{P (a)}{P(e')}

     P(a | e') =  \frac{P (a)}{1- P(e)}

=>   P(a | e') =  \frac{ 0.20}{1- 0.10}

=>   P(a | e') =  0.22

Generally the new probability of companies B  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(b | e') =  \frac{P (b \  and \  e')}{P(e')}

      P(b | e') =  \frac{P (b)}{P(e')}

     P(b | e') =  \frac{P (b)}{1- P(e)}

=>   P(b | e') =  \frac{ 0.25}{1- 0.10}

=>   P(b | e') =  0.28

Generally the new probability of companies C  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(c | e') =  \frac{P (c \  and \  e')}{P(e')}

      P(c | e') =  \frac{P (c)}{P(e')}

     P(c | e') =  \frac{P (c)}{1- P(e)}

=>   P(c | e') =  \frac{ 0.15}{1- 0.10}

=>   P(c | e') =  0.17

Generally the new probability of companies D  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(d | e') =  \frac{P (d \  and \  e')}{P(e')}

      P(d | e') =  \frac{P (d)}{P(e')}

     P(d | e') =  \frac{P (d)}{1- P(e)}

=>   P(d | e') =  \frac{ 0.30}{1- 0.10}

=>   P(c | e') =  0.33

Generally the probability that  B, D , E  are not chosen this year is mathematically represented as

      P(N) =  1 - [P(e) +P(b) + P(d) ]

=>       P(N) =  1 - [0.10 +0.25  +0.30 ]

=>       P(N) =  0.35

Generally the probability that A is chosen given that E , D , B  are rejected this year is mathematically represented  as

      P(a | e' , d' , b') =  \frac{P(a)}{P(N)}

=>     P(a | e' , d' , b') =  \frac{0.20 }{0.35 }    

=>     P(a | e' , d' , b') = 0.57

5 0
3 years ago
find the equation of a circle which passes through the point (2,-2) and (3,4) and whose centre lies on the line x+y=2
Nadusha1986 [10]

Answer:

Equation of the circle

(x - 0.7)² + (y - 1.3)² = 12.58

Step-by-step explanation:

The formula for the equation of a circle is given as:

(x - a)² + (y - b)² = r²,

where(a, b) is the center of the circle and r = radius of the circle.

a) We are told in the question that the equation of the circle passes through point(2, -2)

Hence,

Substituting 2 for x and -2 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(2 - a)² +(-2 - b)² = r²

Expanding the bracket

(2 - a) (2 - a) + (-2 - b)(-2 - b) = r²

4 - 2a - 2a +a² +4 +2b +2b +b² = r²

4 - 4a + a² + 4 + 4b + b² = r²

a² + b² -4a + 4b + 4 + 4 = r²

a² + b² -4a + 4b + 8 = r²............Equation 1

We are also told that the equation of the circle also passes through point (3,4) also, where 3 = x and 4 = y

Hence,

Substituting 3 for x and 4 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(3 - a)² +(4 - b)² = r²

Expanding the bracket

(3 - a) (3 - a) + (4 - b)(4- b) = r²

9 - 3a - 3a +a² +16 -4b -4b +b² = r²

9 -6a + a² + 16 -8b + b² = r²

a² + b² -6a -8b + 9 + 16 = r²

a² + b² -6a -8b + 25 = r²..........Equation 2

The next step would be to subtract Equation 1 from Equation 2

a² + b² -4a + 4b + 8 - (a² + b² -6a -8b + 25) = r² - r²

a² + b² -4a + 4b + 8 - a² - b² +6a +8b - -25= r² - r²

Collecting like terms

a² - a² + b² - b² - 4a + 6a + 4b + 8b +8- 25 = 0

2a + 12b -17 = 0

2a + 12b = 17...........Equation 3

Step 2

We are going to have to find the values of a and b in other to get our equation of the circle.

Since the center of the circle(a, b) lies on x + y = 2

Therefore, we have

a + b = 2

a = 2 - b

2a + 12b = 17 ..........Equation 3

Substituting 2 - b for a in

2(2 - b) + 12b = 17

4 - 2b + 12b = 17

4 + 10b = 17

10b = 17 - 4

10b = 13

b = 13/10

b = 1.3

Substituting 1.3 for b in

a + b = 2

a + 1.3 = 2

a = 2 - 1.3

a = 0.7

hence, a = 0.7, b = 1.3

Step 3

We have to find the value of r using points (2, -2)

(x - a)² + (y - b)² = r²

Where x = 2 and y = -2

(-2 - 0.7)² + (-2 - 1.3)² = r²

(-2.7)² + (-3.3)² = r²

1.69 + 10.89 = r²

r² = 12.58

r = √12.58 = 3.55

Step 4

The formula for the equation of a circle is given as:

(x - a)² + (y - b)² = r²,

where(a, b) is the center of the circle and r = radius of the circle

a = 0.7

b = 1.3

r² = 12.58

Equation of the circle =

(x - 0.7)² + (y - 1.3)² = 12.58

7 0
4 years ago
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