The line g(x) has slope ...
(change in y)/(change in x) = (-18 -(-20))/(1 - 0) = 2
so can be written in slope-intercept form as
g(x) = 2x -20
The x-intercept of this line is at x=10.
0 = 2x -20 . . . . the x-intercept is where g(x) = 0
20 = 2x
10 = x
The circle also intersects the x-axis at x=10, so that will be one point that is shared by the circle and g(x). A graph shows there is also another point of intersection, (6, -8).
Yes, the linear function g(x) will intersect the circle at 2 points with positive x-coordinates.
Answer:
centre = (-5, -4)
radius = 7.42
Step-by-step explanation:
The general form for center-radius is
(x - h)² + (y - k)²= r²
Center = (h, k)
Radius = r
Rearrange the equation.
(x² + 10x) + (y² + 8y) - 14 = 0
Add 14 on both sides.
(x² + 10x) + (y² + 8y) = 14
(10/2)² = 25
(8/2)² = 16
Add 25 and 16 to both sides.
(x² + 10x + 25) + (y² + 8y + 16) = 14 + 25 + 16
Factor left side of the equation.
(x+5)² + (x+4)² = 55
(55) = (7.416198)²
(x+5)² + (x+4)² = 7.42²
The radius is 7.42.
The centre is at (-5, -4).