Whatever the frequency is, that's how many tally marks you put.
The first if a twisted version of a Fibonacci sequence :P
If a1=1.2 and a2=2.3 and a(n)=a(n-1)+a(n-2)
a3=3.5, a4=5.8, a5=9.3
So the first five terms are: 1.2, 2.3, 3.5, 5.8, 9.3
The second is another modified Fibonacci sequence...
If a3=-5 and a4=3 then:
3=-5+a2, a2=8
-5=8+a1, a1=-13
a5=-5+3=-2
a6=-2+3=1
So the first six terms are -13, 8, -5, 3, -2, 1
Answer & Step-by-step explanation:
The confidence interval formula is:
I (1-alpha) (μ)= mean+- [(t(n-1))* S/sqrt(n)]
alpha= is the proportion of the distribution tails that are outside the confidence interval. In this case, 5%.
t(n-1)= t(34)= is the critical value of the t distribution with n-1 degrees of freedom for an area of alpha/2 (2.5%). In this case is 2.032
S= sample standard deviation because the problem does not specify that the standard deviation is from the population. In this case $17.32
mean= $63.57
n= number of observations =35
Then, the confidence interval (90%):
I 95%(μ)= 63.57+- [2.032*(17.32/sqrt(35))
I 95%(μ)= 63.57+- [5.95)
I 95%(μ)= [63.57-5.95; 63.57+5.95]
I 95%(μ)= [57.62; 69.52]
Answer:
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
60÷3 = 20
60÷4=15
60÷5=12
