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fiasKO [112]
3 years ago
11

After 8 years, what is the total amount of a compound interest investment of$25,000 at 3% interest compounded quarterly?

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0

Your question: After 8 years, what is the total amount of a compound interest investment of $25,000 at 3% interest compounded quarterly?

Answer: <u>$31,752.78</u>

Good luck mate. <u>Remember to look through notes and so-forth.</u>

vlada-n [284]3 years ago
4 0
Is there multiple choice?
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Find the difference -9.6-7.3
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-9.6-7.3 = -16.9

Step-by-step explanation:

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3 years ago
Find the dimensions of a rectangle, length 7m less than three times the width and the area of the rectangle is 66m^2.
zhuklara [117]

  We know: length of a rectangle is 7m less than three times the width.

So let's set the length to l, width to w.

And we can get that l = 3w-7.

We also know that the area of the rectangle is 66 m^2.

Thus, l*w= 66.

So we have:

function 1: l=3w-7

function 2: l*w=66

plug function 1 to 2.

(3w-7)*w=66

3w^2-7w-66=0

w=6 and -11/3.

And the width of a rectangle can not be negative.

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Plug w=6 back to function 1 or 2, either way is correct and can give you the length. In this case, I will plug it back to function 1.

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5 0
3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
Find the domain and the range of the relation and determine whether it is a function.
Jobisdone [24]
Domains: 7, -7, 1, 3
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It is a function because all of the domains are different numbers. If they were the same then this would not be a function.
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