Question

Solve for both systems: x + 5y = 7 and x + 3y = 1

Answer 1

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Answer 2

$x+5y=7 \\ x+3y=1 \ \ \ \ \ \ \ \ \ \ \ |\times (-1) \\ \\ x+5y=7 \\ \underline{-x-3y=-1} \\ 5y-3y=7-1 \\ 2y=6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\div 2 \\ y=3 \\ \\ x+3y=1 \\ x+3 \times 3=1 \\ x+9=1 \ \ \ \ \ \ \ \ \ \ \ \ \ |-9 \\ x=-8 \\ \\ \boxed{(x,y)=(-8,3)}$