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jenyasd209 [6]
4 years ago
15

There are 100 runners entered in a marathon. How many different groups of three runners can finish in first, second, and third?

Does this problem involve permutations or combinations?
Mathematics
1 answer:
Lelu [443]4 years ago
3 0
Any one of the runners could be 1st.
Every runner except for the one that was 1st could be 2nd.
Every runner that wasn't 1st or 2nd could be 3rd.

100*99*98=970200 groups.
This involves permutations because order does matter.

Hope this helps!
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Convert 7.23 to a fraction
sladkih [1.3K]
723/100 is the answer to your question!
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3 years ago
Factor the polynomial expression 4x3 - 4.
Sloan [31]
<h3>Answer:  4(x - 1)(x^2 + x + 1)</h3>

==================================================

Work Shown:

4x^3 - 4

4(x^3 - 1)

4(x - 1)(x^2 + x + 1)

In the last step, I used the difference of cubes factoring formula which is

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

3 0
3 years ago
If x is 5, then 6x= __.
Misha Larkins [42]

Answer:

30

Step-by-step explanation:

Plug in x:

6(5)=30

5 0
3 years ago
Read 2 more answers
Need help with my math, please jog my memory.. its been so long since I've done scientific notation. Just answer a few,, thats a
Scrat [10]

Answer:

Down below, look at the explanation, those are the answers.

Step-by-step explanation:

1) 8 * 10 to the power of 0

2) 5.4 * 10 to the power of 1

3) 2 * 10 to the power of -2

4) 2.29 * 10 to the power of 2

5) 1.87 * 10 to the power of 2

6) 4.52 * 10 to the power of -1

7) 6.009 * 10 to the power of -3

8) 4.52 * 10 to the power of 2

9) 3.5710 * 10 to the power of 4

10) 5.026 *10 to the power of -5

11) 7.87 * 10 to the power of 5

12) 4.52 * 10 to the power of 1

13) 9.345 * 10 to the power of 2

14) 4.52 * 10 to the power of -7

15) 1.1235 * 10 to the power of 10

Hope it helps!!

Let me know if I'm wrong...

8 0
3 years ago
Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
navik [9.2K]

ANSWER


The possible rational roots are:


\pm\frac{1}{2},\pm2,\pm \frac{5}{2}


EXPLANATION


According to the rational root theorem, the possible rational roots of the polynomial,



4x^3+9x^2-x+10=0


are all the possible factors of the constant term divided by all the possible factors of the coefficient of the highest degree of the polynomial.



Therefore we examine the numerator and denominator of the options provided to see if they are factors of 10 and 4 respectively.



For

\pm\frac{1}{2}, we can see that 1 is a factor of 10 and 2 is a factor of 4, hence it is a possible rational root.


The same thing applies to \pm2,\pm \frac{5}{2} also.


As for


\pm \frac{2}{5}, 2 is a factor of 10 but 5 is not a factor of 2, hence it is not a possible rational root.


5 0
3 years ago
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