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34kurt
3 years ago
10

Role-playing games like dungeons & dragons use many different types of dice. suppose that a eight-sided die has faces marked

1, 2, 3, 4, 5, 6, 7, 8. the intelligence of a character is determined by rolling this die twice and adding 1 to the sum of the spots. the faces are equally likely and the two rolls are independent. what is the average (mean) intelligence for such characters?
Mathematics
1 answer:
sergejj [24]3 years ago
4 0
In this question, you are given the number of dice faces(8 faces) and the number of the roll( 2 rolls then add 1 value). You are asked the average value.

First, you need to count the average value of the dice probability. Since the lowest possible is 1 and the highest possible is 8, then the dice average value would be: (1+8)/2= 4.5

Then, the average intelligence of the character would be : 2 dice +1 = 2(4.5) +1 = 10 intelligence
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6 0
2 years ago
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ahrayia [7]

Answer:

r = \frac{1}{4}

Step-by-step explanation:

Given the proportional equation

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Divide both sides by x

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Use any ordered pair from the table.

Using (8, 2 ) , then

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8 0
2 years ago
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Helpppppppppppppp my cousins work
SIZIF [17.4K]
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7 0
3 years ago
I need the answer of this with steps and solutions fast plz​
Natali [406]

Answer:

1 \dfrac{13}{15}

Step-by-step explanation:

2 \dfrac{1}{5} - \dfrac{1}{3} =

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6 0
3 years ago
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garik1379 [7]
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8 0
3 years ago
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