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Flura [38]
3 years ago
11

Is this a permutation or combination problem:

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

permutation is the correct one.

Reason: combination are used to calculate the number of possible selections of  objects without regard to the order selected.  "My fruit salad is a combination of apples, grapes, and  bananas". No matter the order, it is still a fruit salad. - The friends cannot be repeated twice so it is not combination

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Simplify the equation -4d - 37 = 7d + 18
exis [7]

Answer:

d=-5

Step-by-step explanation:

-4d-37=7d +18

move the terms to its correct side

-4d-7d=18+37

calculate the like terms together.

-11d=55

divide both sides by -11. both of the negavtive (-11) will cancel out and become d on the left and on the right 55 will be divided by -11 = -5. the 5 is negative because there's a negative -11 if there were a postive 11 it will be 5 instead of D=-5

5 0
3 years ago
Read 2 more answers
Someone help and plz make sure it’s right plz! :)
kvv77 [185]

Answer:

-21/4

Step-by-step explanation:

slope = y2-y1/ x2-x1

-18 - 3 / 17-13 = -21/4

4 0
3 years ago
What is the value of 5 1/3 ​ - 4 12<br> Help
PIT_PIT [208]
4 < 5 < 12
4 is less than 5 is less than 12
4/
1
< 5/
1
< 12/
1
7 0
2 years ago
Read 2 more answers
5+2x15+1-6/76^3x2+73*0+0.0000273
NemiM [27]
  • 6+2(15)+1-6/(76^2×2)+73×0+0.0000273
  • 6+30+1-6/11552+0+0.0000273
  • 37-0.000519+0.0000273
  • 36.999

Done

6 0
2 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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