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Flura [38]
3 years ago
11

Is this a permutation or combination problem:

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

permutation is the correct one.

Reason: combination are used to calculate the number of possible selections of  objects without regard to the order selected.  "My fruit salad is a combination of apples, grapes, and  bananas". No matter the order, it is still a fruit salad. - The friends cannot be repeated twice so it is not combination

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The law of sines states that if a triangle with sides a,b, and c, then the following is true.
Andrej [43]
C, because that’s the way to prove the law of sines.
7 0
3 years ago
Read 2 more answers
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
PLEASE Factor the polynomial completely <br> 8v^2-60v-32
lord [1]
The answer is (4v+2)*(2v-16)
3 0
3 years ago
I don’t get it. <br> Use the net to find the lateral area of the prism.
sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below.  Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.


now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.


we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.


\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}&#10;\\\\\\&#10;90+180\implies 270

6 0
3 years ago
4•f(6)-6•g(5)=?<br> i need help ASAP!
adell [148]

Answer:

6

Step-by-step explanation:

f(6) from the graph is -6

g(5) from the graph is -5

4*f(6)-6*g(5)=(4)(-6)-(6)(-5)=-24+30=6

5 0
2 years ago
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