I know that’s a should be one of them
Answer:
75% bigger
Step-by-step explanation:
Let the first number be x and the second be y.
So:
And:
-----30% less than x
Substitute in
Cross multiply
Collect like terms
Make x the subject
So, the average is:
Rewrite as:
Express as percentage
This means that the average is 75% bigger than the second number
The distributive property of 18(12), or simply 18 * 12, is 216. (This is your answer.)
Note: I'm afraid I can't put the work for the answers, for lack of time =/
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1. 0 or -3
2. 0 or 4
3. -2 or 3
4. 0 or 1/2
5. -2 or 3
6. 0 or 5
7. 0 or 7
8. 0 or -2
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9. Substitute 0 for h in "h = -16x^2 + 16x" then solve for x
0 = -16x^2 + 16x
<span>Subtract -16x^2+16x from both sides.
</span><span>0−<span>(<span><span>−<span>16x2</span></span>+16x</span>)</span></span>=<span><span><span>−<span>16<span>x2</span></span></span>+<span>16x</span></span>−<span>(<span><span>−<span>16x2</span></span>+16x</span>)
</span></span><span><span>16<span>x2</span></span>−<span>16x</span></span>=<span>0
</span>
Factor the left side of the equation
<span><span>16x</span><span>(<span>x−1</span>)</span></span>=<span>0
</span>
Set factors to equal 0
<span><span>16x</span>=<span><span><span>0<span> or </span></span>x</span>−1</span></span>=<span>0
</span>x = 0 or x = 1
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
