Question

PLEASE ANSWER QUICKLY I DO NOT NEED AN EXPLANATION JUST THE RIGHT ANSWER

Answer 1

Final Answer = D. y = -3 +- SR5x+7/2

Answer 2

Answer: $y=-3+-\sqrt{5x+\frac{7}{2}}$

Step-by-step explanation: Given equation $5y+4=(x+3)^2+\frac{1}{2}$.

We need to find it's inverse.

In order to find the inverse, we need to switch x and y's and solve for y.

Step 1: Switching x and y's, we get

$5x+4=(y+3)^2+\frac{1}{2}$

Step 2: Solving it for y.

Subtracting $\frac{1}{2}$ from both sides, we get

$5x+4-\frac{1}{2}=(y+3)^2+\frac{1}{2}-\frac{1}{2}$

$5x+4-\frac{1}{2}=(y+3)^2$

$5x+\frac{8}{2}-\frac{1}{2}=(y+3)^2$

$5x+\frac{7}{2}=(y+3)^2$

Taking square root on both sides, we get

$\sqrt{5x+\frac{7}{2}}=\sqrt{(y+3)^2}$

$\sqrt{5x+\frac{7}{2}}=y+3$

Subtracting 3 from both sides, we get

$\sqrt{5x+\frac{7}{2}}-3=y$

Switching sides, we get

$y=-3+-\sqrt{5x+\frac{7}{2}}$

Therefore, correct option is D option $y=-3+-\sqrt{5x+\frac{7}{2}}$.