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Aleks04 [339]
3 years ago
8

Complete the pattern

Mathematics
2 answers:
Mademuasel [1]3 years ago
8 0
38 x 1 = 1
38 x 0.1 = 3.8
38 x 0.01 = 0.38
Valentin [98]3 years ago
8 0
The pattern is
38x1=38
38x0.1=3.8
38x0.01=0.38
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What is the sum of a geometric sequence 1,3,9,... if there are 14 terms
Maksim231197 [3]
1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323.
If this is the proper sequence pattern, we add up all the numbers to get a sum.
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7 0
3 years ago
Helppppp pls im stuck on thi one problem :(
Ray Of Light [21]

First, find the simplified ratio of the given ratio:

Number of pirates: 22

Number of ships: 2

Divide 22 with 2 to find the ratio: 22/2 = 11

For every ship there is, there will be 11 pirates.

Now, find the ratio for the other questions:

IF there are 5 ships: 5 x 11 = 55

If there are 5 ships, there will be 55 pirates.

If there are 11 ships: 11 x 11 = 121

If there are 11 ships, there will be 121 pirates.

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5 0
3 years ago
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An electronics store reduced the price of a TV from $1200 to $1068. What was the percent of decrease? (please explain the formul
elena-s [515]
You take the difference so 1200-1068=132 and then you take the original divided by the difference so 1200/132 so it would be 9.09%
6 0
3 years ago
What is the solution to the inequality 14y−14≥14?
makkiz [27]
14y > 0 is the answer
6 0
3 years ago
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A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
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