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dmitriy555 [2]
3 years ago
7

I need help with this its for a math quiz please

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:c

Step-by-step explanation:

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There will need to be 9 groups of 7
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⦁ The population of the Tallahassee metropolitan area was 382,627 at the end of 2017 with a growth rate of 2.78%. Using the expo
a_sh-v [17]

Answer:

The exponential growth model for the population of the Tallahassee metropolitan area is y=382627(1.0278)^t.

Step-by-step explanation:

The exponential formula is

y=b(1+r)^t

Where b is initial population, r is growth rate, (1+r) is growth factor and t is time (in years) after the initial year.

The population of the Tallahassee metropolitan area was 382,627 at the end of 2017. The growth rate is 2.78%.

Here the initial year is 2017 and rate is 0.0278

y=382627(1+0.0278)^t

y=382627(1.0278)^t

Graph of the equation is shown below. The x-axis represents the number of years after 2017 and y-axis represents the total population.

Difference between 2025 and 2017 is 8 years. Put t=8

y=382627(1.0278)^8

y=382627(1.0278)^8

y=476479.828188\approx 476479

Therefore the projected population in 2025 is 476479.

7 0
4 years ago
a fireplace contains 54 bricks along its bottom row. if each row above decreases by 3 bricks, what is the function that shows th
Norma-Jean [14]

Step-by-step explanation:

the fireplace would have 24 bricks on the 10th row

6 0
3 years ago
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Let C(t) be the concentration of a drug in the bloodstream. As the body eliminates the drug, C(t) decreases at a rate that is pr
tia_tia [17]

Answer:

See explanation below

Step-by-step explanation:

In this case, let's answer this by parts:

<u>a) Concentration at time t when Co  is concentration at t = 0:</u>

In this case, we will use the initial expression but without the 2, so:

C(t) = -kC

In this case, we want to know the concentration at time t so:

C'(t) = -kC(t)    derivating:

dC/dt = -kC

dC/C = -kdt   From here, we can do integrals so:

lnC = -kt + C₁   (1)

Now, it's time to replace t = 0 and C = C₀:

lnC₀ = -k(0) + C₁

lnC₀ = C₁   (2)

Replacing (2) in (1) we have:

lnC = -kt + lnC₀

lnC - lnC₀ = -kt

ln(C/C₀) = -kt

C/C₀ = e^(-kt)

C(t) = C₀ e^(-kt)   (3)

This is the expression for C at given time t.

<u>2. time to eliminate 80% of the drug:</u>

With the first data, we need to calculate the value of k, which will be constant at any given time so:

C(t) = C₀ e^(-kt)

0.5C₀ = C₀ e^(-30k)

0.5 = e^(-30k)

ln(0.5) = -30k

k = 0.02310

Now with this value we can calculate the time to eliminate 80% of the drug or simply in other words, that we just have a remaining of 0.2C₀:

0.2C₀ = C₀ e^(-0.0231t)

ln(0.2) = -0.0231t

-ln(0.2) / 0.0231 = t

t = 69.67 h

This is the time to eliminate 80% of the drug

8 0
3 years ago
Diffrentiate Insin³x​
faltersainse [42]

Step-by-step explanation:

ln((sin(x))^3)'

Chen Lu

= (((sin(x))^3)' / (sin(x))^3

Chen Lu

=(3sin²(x)cos(x)/ (sin(x))^3

= 3cos(x)/sin(x)

=3cot(x)

8 0
3 years ago
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